Laboratory Manual Chemistry in Context
8th Edition
ISBN: 9780073518121
Author: American Chemical Society
Publisher: McGraw-Hill Education
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Question
Chapter 9, Problem 6Q
Interpretation Introduction
Interpretation:
The way how two bottles given in figure 9.3a differs at molecular level has to be identified.
Concept Introduction:
Monomers combine together to form polymers. Monomers are the repeating units of small molecules which link together to form polymers and the process is called as
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Solution
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Use retrosynthetic analysis to suggest two paths to synthesize 2-methyl-3-hexanol using the Grignard reaction. (Click and drag
the appropriate image to the correct position in the reactions.)
Route 1
Aldehyde 1
or
+98
Aldehyde 2
Route 2
Q6
+100
Solved in 1 attempt
Q7
+95
Solved in 2 attempts
Q8
+98
Unlimited attempts
possible
+
+
Grignard 1
OH
H3O+
Grignard 2
Answer Bank
Q9
+90
MgBr
Unlimited attempts
possible
CH3CH2CH2MgBr
Q10
Unlimited attempts
Q11
?
?
+100
in 1 attempt
2-methyl-3-hexanol
CH3CH2MgBr
H
H
о
H
Attempt 3
2) (4 pt) After the reaction was completed, the student collected the following data. Crude
product data is the data collected after the reaction is finished, but before the product
is purified. "Pure" product data is the data collected after attempted purification using
recrystallization.
Student B's data:
Crude product data
"Pure"
product data
after
recrystallization
Crude mass: 0.93 g grey solid
Crude mp: 96-106 °C
Crude % yield:
Pure mass: 0.39 g white solid
Pure mp: 111-113 °C
Pure % yield:
a) Calculate the crude and pure percent yields for the student's reaction.
b) Summarize what is indicated by the crude and pure melting points.
Don't used hand raiting
Chapter 9 Solutions
Laboratory Manual Chemistry in Context
Ch. 9.1 - Scientific Practices Tennis Anyone? Examine this...Ch. 9.1 - Prob. 9.2CTCh. 9.4 - Prob. 9.4YTCh. 9.4 - Prob. 9.5CTCh. 9.4 - Prob. 9.6CTCh. 9.4 - Prob. 9.7CTCh. 9.4 - Prob. 9.8CTCh. 9.5 - Prob. 9.9CTCh. 9.5 - Prob. 9.11CTCh. 9.5 - Skill Building Polystyrene Possibilities Show the...
Ch. 9.6 - Skill Building Esters and Polyesters You have seen...Ch. 9.6 - Prob. 9.14CTCh. 9.7 - Skill Building Kevlar Kevlar is a polyamide used...Ch. 9.8 - Prob. 9.18CTCh. 9.8 - Your Turn 9.23 Scientific Practices Landfill...Ch. 9.9 - Prob. 9.23YTCh. 9.9 - Prob. 9.24CTCh. 9.11 - Your Turn 9.31 Scientific Practices Glass or...Ch. 9.11 - Prob. 9.29CTCh. 9.11 - Skill Building Meet DEHP DEHP belongs to a common...Ch. 9 - Prob. 1QCh. 9 - Prob. 2QCh. 9 - Prob. 3QCh. 9 - Prob. 4QCh. 9 - Prob. 5QCh. 9 - Prob. 6QCh. 9 - Prob. 7QCh. 9 - Prob. 8QCh. 9 - Prob. 9QCh. 9 - Prob. 10QCh. 9 - Prob. 11QCh. 9 - Prob. 12QCh. 9 - Prob. 13QCh. 9 - Prob. 14QCh. 9 - Prob. 15QCh. 9 - Prob. 16QCh. 9 - Prob. 17QCh. 9 - Prob. 18QCh. 9 - Prob. 19QCh. 9 - Prob. 20QCh. 9 - Prob. 21QCh. 9 - Prob. 22QCh. 9 - Prob. 23QCh. 9 - Prob. 24QCh. 9 - Prob. 25QCh. 9 - Prob. 26QCh. 9 - Prob. 27QCh. 9 - Prob. 28QCh. 9 - Prob. 29QCh. 9 - Prob. 30QCh. 9 - Prob. 31QCh. 9 - Prob. 32QCh. 9 - Prob. 33QCh. 9 - Prob. 34QCh. 9 - Prob. 35QCh. 9 - Prob. 36QCh. 9 - Prob. 37QCh. 9 - Prob. 38QCh. 9 - Prob. 39QCh. 9 - Prob. 40QCh. 9 - Prob. 41QCh. 9 - Prob. 42QCh. 9 - Prob. 43QCh. 9 - Prob. 44QCh. 9 - Prob. 45QCh. 9 - Prob. 46QCh. 9 - Prob. 47QCh. 9 - Prob. 48QCh. 9 - Prob. 49QCh. 9 - Prob. 50QCh. 9 - Prob. 51QCh. 9 - Prob. 52QCh. 9 - Prob. 53QCh. 9 - Prob. 54QCh. 9 - Prob. 55QCh. 9 - Prob. 56QCh. 9 - Prob. 57QCh. 9 - Prob. 58QCh. 9 - Prob. 59Q
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- A DEPT NMR spectrum is shown for a molecule with the molecular formula of C5H12O. Draw the structure that best fits this data. 200 180 160 140 120 100 一盆 00 40 8- 20 ppm 0 Qarrow_forwardDon't used hand raitingarrow_forwardShown below is the major resonance structure for a molecule. Draw the second best resonance structure of the molecule. Include all non-zero formal charges. H. H. +N=C H H H Cl: Click and drag to start drawing a structure. : ? g B S olo Ar B Karrow_forward
- Don't used hand raitingarrow_forwardS Shown below is the major resonance structure for a molecule. Draw the second best resonance structure of the molecule. Include all non-zero formal charges. H H = HIN: H C. :0 H /\ H H Click and drag to start drawing a structure. ×arrow_forwardPlease help me figure out these calculation and what should be plotted. These are notes for my chemistry class.arrow_forward
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