Anatomy & Physiology: The Unity of Form and Function
8th Edition
ISBN: 9781259277726
Author: Kenneth S. Saladin Dr.
Publisher: McGraw-Hill Education
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Chapter 9, Problem 15TYR
Summary Introduction
Introduction:
A fibrous joint is a connection between the two bones made of dense connective tissue collagen. A gomphosis is a specialized type of joint where the root of the tooth anchors into the bony socket of the maxillaeand mandible.It is a type of immovable joint and functionally belongs to the synarthrosis.
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a) Calculating Transformation Efficiency
For the +DNA/+Amp/+IPTG plate, record the following:
Number of transformants (colonies): _________________
Nanograms of plasmid DNA added: 50 ng
Final recovery volume: 0.50 mL
Volume plated: 0.25 mL
Transformation efficiency equation:
Transformation efficiency = Number of transformants / µg of DNA x Final volume at recovery (mL)/ volume plated (mL)
b) Using the equation above, calculate the transformation efficiency.
c) Describe the success of the transformation efficiency of this demo based on the calculation you did above?
a) What differences would you expect to see between the -DNA/+Amp and +DNA/+Amp plates?
b) Predict the growth you would expect to see on each of the following plates:
– DNA ___________________________________________________________
– DNA/+Amp ______________________________________________________
+DNA/+Amp ______________________________________________________
+DNA/+Amp/+IPTG _________________________________________________
1)Which plate did you see purple/pink/blue bacterial cells? Why did you see this growth? Explain your answer in terms of transformation and plasmids?
2) Calculating Transformation Efficiency
For the +DNA/+Amp/+IPTG plate, record the following:
Number of transformants (colonies): _________________
Nanograms of plasmid DNA added: 50 ng
Final recovery volume: 0.50 mL
Volume plated: 0.25 mL
Transformation efficiency equation:
Transformation efficiency = Number of transformants / µg of DNA x Final volume at recovery (mL)/ volume plated (mL)
3) Using the equation above, calculate the transformation efficiency.
4) Describe the success of the transformation efficiency of this demo based on the calculation you did above?
Chapter 9 Solutions
Anatomy & Physiology: The Unity of Form and Function
Ch. 9.1 - The fundamental definition of joint (articulation)...Ch. 9.1 - Relationships and differences between the sciences...Ch. 9.1 - Prob. 3AYLOCh. 9.1 - Prob. 4AYLOCh. 9.1 - Characteristics and examples of bony joints...Ch. 9.1 - Characteristics of fibrous joints (synarthroses)...Ch. 9.1 - Characteristics of cartilaginous joints...Ch. 9.2 - The definition and anatomical features of a...Ch. 9.2 - General anatomy of tendons, ligaments, bursae, and...Ch. 9.2 - Three essential components of a lever
Ch. 9.2 - Prob. 4AYLOCh. 9.2 - Prob. 5AYLOCh. 9.2 - Variables that determine a joints range of motion...Ch. 9.2 - Prob. 7AYLOCh. 9.2 - Six kinds of synovial joints; how each is...Ch. 9.2 - The concept of zero position and how it relates to...Ch. 9.2 - Prob. 10AYLOCh. 9.2 - Prob. 11AYLOCh. 9.2 - The same for flexion, extension, hyperextension,...Ch. 9.2 - Prob. 13AYLOCh. 9.2 - Prob. 14AYLOCh. 9.2 - Prob. 7BYGOCh. 9.2 - Prob. 8BYGOCh. 9.3 - Features of the jaw (temporomandibular) joint...Ch. 9.3 - Features of the shoulder (glenohumeral) joint...Ch. 9.3 - Prob. 3AYLOCh. 9.3 - Prob. 4AYLOCh. 9.3 - Prob. 5AYLOCh. 9.3 - Features of the ankle (talocrural) joint,...Ch. 9 - Prob. 1TYRCh. 9 - Which of the following is the least movable? a. a...Ch. 9 - Prob. 3TYRCh. 9 - Prob. 4TYRCh. 9 - Which of the following terms denotes a general...Ch. 9 - Prob. 6TYRCh. 9 - In a second-class lever, the effort a. is applied...Ch. 9 - Prob. 8TYRCh. 9 - Prob. 9TYRCh. 9 - The rotator cuff includes the tendons of all of...Ch. 9 - Prob. 11TYRCh. 9 - A fluid-filled sac that eases the movement of a...Ch. 9 - Prob. 13TYRCh. 9 - _____ is the science of movement.Ch. 9 - Prob. 15TYRCh. 9 - Prob. 16TYRCh. 9 - Prob. 17TYRCh. 9 - Prob. 18TYRCh. 9 - Prob. 19TYRCh. 9 - Prob. 20TYRCh. 9 - Prob. 1BYMVCh. 9 - Prob. 2BYMVCh. 9 - Prob. 3BYMVCh. 9 - Prob. 4BYMVCh. 9 - Prob. 5BYMVCh. 9 - Prob. 6BYMVCh. 9 - Prob. 7BYMVCh. 9 - Prob. 8BYMVCh. 9 - Prob. 9BYMVCh. 9 - Prob. 10BYMVCh. 9 - Prob. 1WWTSCh. 9 - A doctor who treats arthritis is called a...Ch. 9 - Prob. 3WWTSCh. 9 - Prob. 4WWTSCh. 9 - Prob. 5WWTSCh. 9 - Prob. 6WWTSCh. 9 - Prob. 7WWTSCh. 9 - Prob. 8WWTSCh. 9 - Synovial fluid is secreted by the bursae.Ch. 9 - Prob. 10WWTSCh. 9 - All second-class levers produce a mechanical...Ch. 9 - For each of the following joint movements, state...Ch. 9 - In order of occurrence, list the joint actions...Ch. 9 - Prob. 4TYCCh. 9 - Prob. 5TYCCh. 9 - Prob. 1BYGOCh. 9 - Prob. 2BYGOCh. 9 - Prob. 3BYGOCh. 9 - Prob. 4BYGOCh. 9 - Prob. 5BYGOCh. 9 - Prob. 6BYGOCh. 9 - Prob. 7BYGOCh. 9 - Prob. 8BYGOCh. 9 - Prob. 9BYGOCh. 9 - Prob. 10BYGOCh. 9 - Prob. 11BYGOCh. 9 - Prob. 12BYGOCh. 9 - Prob. 13BYGOCh. 9 - Prob. 14BYGOCh. 9 - Prob. 15BYGOCh. 9 - Prob. 16BYGO
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- Overview of Transformation Protocol -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes. Questions: 1) What differences would you expect to see between the…arrow_forwardOverview of Transformation Protocol -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes. Questions: 1)What is the selectable marker in this experiment? How…arrow_forwardBased on your results, which suspect's DNA best matches the DNA found at the crime scene?arrow_forward
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