Chapter 8.4, Problem 42AYU

To determine

To find: The area of the Bermuda triangle.

Answer to Problem 42AYU

The area of the Bermuda triangle is $442,816$ .

Explanation of Solution

Given:

The dimensions of the Bermuda triangle are $\left(1028,1046,965\right)$ .

Calculation:

Consider the semi perimeter for the ground of the building is,

  $s=\frac{1}{2}\left(a+b+c\right)$

Then,

  $\begin{array}{c}s=\frac{1}{2}\left(1028+1046+965\right)\\ =1519.5\end{array}$

Consider the formula for the area of the triangle is,

  $K=\sqrt{s\left(s-a\right)\left(s-b\right)\left(s-c\right)}$

Then,

  $\begin{array}{c}K=\sqrt{1519.5\left(1519.5-1028\right)\left(1519.5-1046\right)\left(1519.5-965\right)}\\ =442,816\end{array}$