Chapter 8, Problem 64RE

To determine

To develop: A model that relates the displacement $d$ of the object.

Explanation of Solution

Given: $a=5;T=6\sec$

The equation of simple harmonic motion is given by,

  $y=a\cos \omega t$

And,

  $\begin{array}{c}T=\frac{2\pi }{\omega }\\ 6=\frac{2\pi }{\omega }\\ \omega =\frac{\pi }{3}\end{array}$

So, the model is,

  $y=5\cos \left(\frac{\pi }{3}t\right)$

Therefore, the model is $y=5\cos \left(\frac{\pi }{3}t\right)$ .