
To find: The time lost due to error.

Answer to Problem 46AYU
The total time loss is of 0.01 .
Explanation of Solution
Given:
The error of the course is 10° .
The distance covered by the aircraft before changing the course is 50 miles .
The distance covered by the aircraft after changing the course is 70 miles .
The constant speed of the aircraft is 250 mi/hr .
The given diagram is shown in Figure 1
Figure 1
Calculation:
Consider the law of sine is,
sinPp=sinQq
Then,
sin10°70=sinQ50sinQ=50(sin10°70)Q=sin−1[50(sin10°70)]Q=7.12
Consider the angle sum property of triangle is,
P+Q+R=180°R+17.12°=180°R=162.88°
Consider the law of sine to find the value of r is,
sin10°70=sin162.88°rr=70[sin162.88°sin10°]r=118.67
Thus, the time taken by the aircraft to cover the distance of 1186.7 miles is,
t=1186.7 mi250 m/h=0.47 hr
The time take to cover the distance of 50 mi and 70 mi is,
t=(50+70)250=0.48 hr
The total time lost is,
t=0.48 hr−0.47 hr=0.01
Chapter 8 Solutions
Precalculus
Additional Math Textbook Solutions
Calculus: Early Transcendentals (2nd Edition)
Introductory Statistics
Elementary Statistics
Algebra and Trigonometry (6th Edition)
Thinking Mathematically (6th Edition)
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