Chapter 8.2, Problem 6QR

To determine

To Find: The $x-$ and $y-$ coordinates of all points where the graphs of the given functions intersect

Answer to Problem 6QR

the points of intersections are $(-1,5)(6,12)$

Explanation of Solution

Given information:

Two functions

  $y=x^2-4x$ and $y=x+6$

Calculation:

Simplifying

  $\begin{array}{l}{x}^2-4x=x+6\\ x^2-5x-6=0\\ (x+1)(x-6)=0\\ x=-1,6\end{array}$

For each of these $x-$ value find the corresponding $y-$ value

  $\begin{array}{l}x=-1,y=5\\ x=6,y=12\end{array}$

Therefore, the points of intersections are $(-1,5)(6,12)$