Chapter 8.3, Problem 66E

To determine

To choose : the correct option.

Answer to Problem 66E

The correct option is (e) $361.9$ .

Explanation of Solution

Given information : Let $R$ be the region in the first quadrant bounded by the graph of $y=8-x^{\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}$ , the axis and the y-axis.

  $\begin{array}{l}V=\pi {\displaystyle \underset{0}{\overset{4}{\int }}{R}^{2}xdx}\\ V=\pi {\displaystyle \underset{0}{\overset{4}{\int }}{\left(\left(8-x^{\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}\right)-0\right)}^{2}xdx}\\ V=361.9\end{array}$