(a) Explanation Given information: The power P is 20 hp . The rotation speed ( ω ) is 360 rpm . The allowable bending stress ( τ all ) is 7.5 ksi Calculation: Refer to problem P8.25: Convert the unit hp to in . lb / s . 1 hp is equal to 550 lbs ⋅ ft / s . 20 hp = 20 × 550 lbs ⋅ ft / s ( 12 in 1 ft ) =132,000 =132 × 10 3 in . lb / s Find the frequency ( f ) as follows: f = N 60 (1) Here, N is the number of revolutions. Substitute 360 rpm for N in Equation (1). f = 360 rpm 60 = 6 Hz Find the value of torque ( T ) for shaft ABC as follows: T = P 2 π f (2) Here, P is the power and f is the frequency. Substitute 132 × 10 3 in . lb / s for P and 6 Hz for f in Equation (2). T = 132 × 10 3 2 π × 6 = 132 × 10 3 37.699 = 3 , 501 lb ⋅ in Gear C: Find the value of F C D as follows: F C D = T r c (3) Here, T is toque and r c is radius at point C . Substitute 3 , 501 lb ⋅ in for T and 6 in . for r c in Equation (3) (b) To determine The smallest permissible diameter of shaft DEF .

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ISBN: 9780100257061

Author: BEER

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Chapter 8.2, Problem 26P

(a)

To determine

The smallest permissible diameter of shaft ABC.

(b)

To determine

The smallest permissible diameter of shaft DEF.

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Chapter 8.2, Problem 25P

Chapter 8.2, Problem 27P

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The smallest permissible diameter of shaft ABC .

Solution Summary: The author calculates the smallest permissible diameter of shaft ABC. The power P is 20hp.