The reason for lower intensity of atomic line for Li in a natural gas flame, 1800 o C in comparison to the hydrogen-oxygen flame, 2700 o C should be determined. Concept introduction: Spectral lines are lines which help in identifying the atoms and molecules. These are a result of absorption or emission of light in a comparatively narrower frequency range compared to the frequencies nearby. With the increase in temperature, there are more atoms excited and more electron transition happens from ground state to excited state. This results in more intensity of the emission line.

Question

bre The reaction sequence shown in Scheme 5 demonstrates the synthesis of a substituted benzene derivative Q. wolsd works 2 NH2 NaNO2, HCI (apexe) 13× (1 HNO3, H2SO4 C6H5CIN2 0°C HOTE CHINO₂ N O *O₂H ( PO Q Я Scheme 5 2 bag abouoqmics to sounde odi WEIC (i) Draw the structure of intermediate O. [2 marks] to noitsmot od: tot meinedogm, noit so oft listsb ni zaupaib bas wa (ii) Draw the mechanism for the transformation of aniline N to intermediate O. Spoilage (b) [6 marks] (iii) Identify the reagent X used to convert compound O to the iodinated compound [tom E P. vueimado oilovonsa ni moitos nolisbnolov ayd toes ai tedw nisiqx (iv) Identify the possible structures of compound Q. [2 marks] [2 marks] [shom 2] (v) bus noires goiribbeolovo xnivollot adj to subora sidab Draw the mechanism for the transformation of intermediate P to compound Q. [5 marks] vi (vi) Account for the regiochemical outcome observed in the reaction forming compound Q. [3 marks]

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Chapter 8, Problem 8.6QAP

Interpretation Introduction

Interpretation:

The reason for lower intensity of atomic line for Li in a natural gas flame, 1800 ^oC in comparison to the hydrogen-oxygen flame, 2700 ^oC should be determined.

Concept introduction:

Spectral lines are lines which help in identifying the atoms and molecules. These are a result of absorption or emission of light in a comparatively narrower frequency range compared to the frequencies nearby.

With the increase in temperature, there are more atoms excited and more electron transition happens from ground state to excited state. This results in more intensity of the emission line.

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bre The reaction sequence shown in Scheme 5 demonstrates the synthesis of a substituted benzene derivative Q. wolsd works 2 NH2 NaNO2, HCI (apexe) 13× (1 HNO3, H2SO4 C6H5CIN2 0°C HOTE CHINO₂ N O *O₂H ( PO Q Я Scheme 5 2 bag abouoqmics to sounde odi WEIC (i) Draw the structure of intermediate O. [2 marks] to noitsmot od: tot meinedogm, noit so oft listsb ni zaupaib bas wa (ii) Draw the mechanism for the transformation of aniline N to intermediate O. Spoilage (b) [6 marks] (iii) Identify the reagent X used to convert compound O to the iodinated compound [tom E P. vueimado oilovonsa ni moitos nolisbnolov ayd toes ai tedw nisiqx (iv) Identify the possible structures of compound Q. [2 marks] [2 marks] [shom 2] (v) bus noires goiribbeolovo xnivollot adj to subora sidab Draw the mechanism for the transformation of intermediate P to compound Q. [5 marks] vi (vi) Account for the regiochemical outcome observed in the reaction forming compound Q. [3 marks]

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