Principles of Instrumental Analysis
7th Edition
ISBN: 9781305577213
Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher: Cengage Learning
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Question
Chapter 8, Problem 8.1QAP
Interpretation Introduction
Interpretation:
To explain the reason for the broader spectrum of CaOH compared to the sodium emission line.
Concept introduction:
Spectral lines help in identifying the atoms and molecules. These are a result of absorption or emission of light in a comparatively narrow frequency range nearby.
Expert Solution & Answer
Answer to Problem 8.1QAP
CaOH spectrum is broader owing to the transitions among the vibrational and rotational states whereas in the case of sodium, the transitions take place among electronic energy states.
Explanation of Solution
CaOH or calcium hydroxide is an ionic molecule where vibrational and rotational levels are possible. Owing to the transitions among the vibrational, rotational states, there exists broad line spectra in case of the CaOH molecule.
In the case of sodium, it is not possible to have the transitions among the vibrational, rotational states. They take place among electronic energy states thus, resulting in a line spectrum.
Conclusion
CaOH spectrum is broader owing to the transitions among the vibrational and rotational states which is not possible in sodium.
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Potentially Useful Information
Spectrochemical Series:
| < Br < SCN¯ < Cl° < NO3¯ < F° < OH° < C2O4²¯ ~ H2O <
NCS° < NH3 < en < PPH3
く
A student has three test tubes containing a metal (M) nitrate solution M(NO3)2 (aq)
(where "M" represents a generic transition metal). The student adds aqueous
ammonia (NH3) to one test tube, aqueous hydrochloric acid (HCI) to the second tube,
and nothing more to the third tube, but forgets to label the tubes. After this, one
test tube contains a red solution, one an orange solution, and one a yellow solution.
Note: This metal, M, would follow the same rules that we used for Cu(II), Ni(II), and Co(II).
The Jahn-Teller Effect does not apply.
Complete each statement or answer each question below about the solutions
in the three test tubes.
The aqua complex causes less splitting of the d orbitals of the metal than the...
ammonia complex.
O chloro complex.
What are the colors of CoC12 and CoC12 6H2O and specify the source used?
Chapter 8 Solutions
Principles of Instrumental Analysis
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