Chemistry for Engineering Students
4th Edition
ISBN: 9781337398909
Author: Lawrence S. Brown, Tom Holme
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 8, Problem 8.67PAE
Interpretation Introduction
Interpretation:
In general, pencil erasers are made of synthetic rubber. Some times to get the special qualities, vinyl, plastic or gum like material are added to rubbers.
Concept introduction: The melting point of rubber is around
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
7. Melting points of Br2 and ICl are - 7.2 and 27.2°C, respectively and their electrons are same.
Explain.
This thermodynamic cycle describes the formation of an ionic compound MX from a metal element M and nonmetal element X in their standard states. Use it to
answer the questions in the table below.
enthalpy
(kJ/mol)
1000.
900.
800.
700.
600.
500.
400.
300.
200.
100.
0.
- 100.
M (g) + X (g)
1
M (g) +
+ = X ₂2 (8)
2
1
M (s) +
+ — — X ₂2 (8)
+
M*(g) + e
1
T
+ x (g)
M+ (8) + X¯¯ (8)
x
MX (s)
Calculate the lattice energy of magnesium sulfide from the data given below.
Mg(s)
Mg(g) AE
148 kJ/mol
Mg2g)
8S(g) AE 2232 kJ/mol
2e AE 2186 kJ/mol
Mg(g)
S8(s)
Sig) 2eSg) AE= 450 kJ/mol
8Mg(s)S8(s) -» 8M9S(s) AE = -2744 kJ/mol
Mg2+(g) S2g)
MgS(s) AElattice = ?
Chapter 8 Solutions
Chemistry for Engineering Students
Ch. 8 - Prob. 1COCh. 8 - • describe the arrangement of atoms in the common...Ch. 8 - • use bind theory to describe bonding in solids.Ch. 8 - Prob. 4COCh. 8 - Prob. 5COCh. 8 - Prob. 6COCh. 8 - Prob. 7COCh. 8 - • explain the connection between intermolecular...Ch. 8 - Prob. 9COCh. 8 - Prob. 10CO
Ch. 8 - Prob. 8.1PAECh. 8 - Why is the C 60form of carbon called...Ch. 8 - Prob. 8.3PAECh. 8 - Prob. 8.4PAECh. 8 - What is the relationship between the structures of...Ch. 8 - Use the web to look up information on nanotubes....Ch. 8 - Prob. 8.7PAECh. 8 - Prob. 8.8PAECh. 8 - Prob. 8.9PAECh. 8 - Prob. 8.10PAECh. 8 - Prob. 8.11PAECh. 8 - Prob. 8.12PAECh. 8 - 8.13 What is the coordination number of atoms in...Ch. 8 - Prob. 8.14PAECh. 8 - Prob. 8.15PAECh. 8 - 8.16 Iridium forms a face-centered cubic lattice,...Ch. 8 - 8.17 Europium forms a body-centered cubic unit...Ch. 8 - 8.18 Manganese has a body-centered cubic unit cell...Ch. 8 - Prob. 8.19PAECh. 8 - 8.20 How many electrons per atom are delocalized...Ch. 8 - Prob. 8.21PAECh. 8 - Prob. 8.22PAECh. 8 - Prob. 8.23PAECh. 8 - 8.24 What is the key difference between metallic...Ch. 8 - 8.25 Draw a depiction of the band structure of a...Ch. 8 - Prob. 8.26PAECh. 8 - Prob. 8.27PAECh. 8 - Prob. 8.28PAECh. 8 - Prob. 8.29PAECh. 8 - Prob. 8.30PAECh. 8 - Prob. 8.31PAECh. 8 - Prob. 8.32PAECh. 8 - Prob. 8.33PAECh. 8 - Suppose that a device is using a 15.0-mg sample of...Ch. 8 - 8.35 What is an instantancous dipole?Ch. 8 - 8.36 Why are dispersion forces attractive?Ch. 8 - 8.37 If a molecule is not very polarizable, how...Ch. 8 - 8.38 What is the relationship between...Ch. 8 - 8.39 Under what circumstances are ion-dipole...Ch. 8 - 8.40 Which of the following compounds would be...Ch. 8 - 8.41 What is the specific feature of N, O, and F...Ch. 8 - Prob. 8.42PAECh. 8 - 8.43 Identify the kinds of intermolecular forces...Ch. 8 - Prob. 8.44PAECh. 8 - 8.45 Describe how interactions between molecules...Ch. 8 - 8.46 What makes a chemical compound volatile?Ch. 8 - 8.47 Answer each of the following questions with...Ch. 8 - 8.48 Why must the vapor pressure of a substance be...Ch. 8 - Prob. 8.49PAECh. 8 - Prob. 8.50PAECh. 8 - 8.51 Suppose that three unknown pure substances...Ch. 8 - 8.52 Rank the following hydrocarbons in order of...Ch. 8 - Prob. 8.53PAECh. 8 - Prob. 8.54PAECh. 8 - Prob. 8.55PAECh. 8 - Prob. 8.56PAECh. 8 - Prob. 8.57PAECh. 8 - Prob. 8.58PAECh. 8 - Prob. 8.59PAECh. 8 - Prob. 8.60PAECh. 8 - 8.61 Distinguish between a block copolymer and a...Ch. 8 - Prob. 8.62PAECh. 8 - Prob. 8.63PAECh. 8 - Prob. 8.64PAECh. 8 - Prob. 8.65PAECh. 8 - 8.66 What structural characteristics are needed...Ch. 8 - Prob. 8.67PAECh. 8 - Prob. 8.68PAECh. 8 - Prob. 8.69PAECh. 8 - Prob. 8.70PAECh. 8 - Prob. 8.71PAECh. 8 - Prob. 8.72PAECh. 8 - Prob. 8.73PAECh. 8 - Prob. 8.74PAECh. 8 - 8.75 Using pentagons, draw arrangements that...Ch. 8 - 8.76 Using circles, draw regular two-dimensional...Ch. 8 - 8.77 What is the difference between a bonding...Ch. 8 - Prob. 8.78PAECh. 8 - 8.79 Most gaseous compounds consist of small...Ch. 8 - 8.80 Why are dipole—dipole forces typically...Ch. 8 - 8.81 Carbon tetrachloride (CCl4) is a liquid at...Ch. 8 - Prob. 8.82PAECh. 8 - Prob. 8.83PAECh. 8 - Prob. 8.84PAECh. 8 - Prob. 8.85PAECh. 8 - Prob. 8.86PAECh. 8 - 8.87 Use the vapor pressure curves illustrated...Ch. 8 - Prob. 8.88PAECh. 8 - 8.89 The following data show the vapor pressure of...Ch. 8 - Prob. 8.90PAECh. 8 - Prob. 8.91PAECh. 8 - Prob. 8.92PAECh. 8 - Prob. 8.93PAECh. 8 - Prob. 8.94PAECh. 8 - Prob. 8.95PAECh. 8 - 8.96 A business manager wants to provide a wider...Ch. 8 - 8.97 The doping of semiconductors can be done with...Ch. 8 - 8.98 If you know the density of material and the...Ch. 8 - Prob. 8.99PAECh. 8 - Prob. 8.100PAECh. 8 - Prob. 8.101PAECh. 8 - Prob. 8.102PAECh. 8 - 8.103 Cryolite (Na3AlF6) is used in refining...Ch. 8 - Prob. 8.104PAECh. 8 - Prob. 8.105PAE
Knowledge Booster
Similar questions
- Bond Enthalpy When atoms of the hypothetical element X are placed together, they rapidly undergo reaction to form the X2 molecule: X(g)+X(g)X2(g) a Would you predict that this reaction is exothermic or endothermic? Explain. b Is the bond enthalpy of X2 a positive or a negative quantity? Why? c Suppose H for the reaction is 500 kJ/mol. Estimate the bond enthalpy of the X2 molecule. d Another hypothetical molecular compound, Y2(g), has a bond enthalpy of 750 kJ/mol, and the molecular compound XY(g) has a bond enthalpy of 1500 kJ/mol. Using bond enthalpy information, calculate H for the following reaction. X2(g)+Y2(g)2XY(g) e Given the following information, as well as the information previously presented, predict whether or not the hypothetical ionic compound AX is likely to form. In this compound, A forms the A+ cation, and X forms the X anion. Be sure to justify your answer. Reaction: A(g)+12X2(g)AX(s)The first ionization energy of A(g) is 400 kJ/mol. The electron affinity of X(g) is 525 kJ/mol. The lattice energy of AX(s) is 100 kJ/mol. f If you predicted that no ionic compound would form from the reaction in Part e, what minimum amount of AX(s) lattice energy might lead to compound formation?arrow_forward5. You are given a list of binary compounds (only two different elements) and asked to determine the relative melting points. a) Which would have the higher melting point, the binary ionic compounds or the binary covalent compounds? Explain your choice? b) If you have two different ionic compounds, like Bal; and Mgo, which would have the higher melting point and why? c) For those compounds that are covalent, which would you expect to have the higher melting point and why (what would you be looking for – give an example)?arrow_forwardThis thermodynamic cycle describes the formation of an ionic compound MX2 from a metal element M and nonmetal element X in their standard states. Based of the table (picture): A. What is the lattice enthalpy of MX2 ? (in kJ/mol) B. What is the enthalpy of formation of MX2 ? (in kJ/mol) C. Suppose both the electron affinity of X and the heat of sublimation of M were smaller. Would MX2 be more or less stable?arrow_forward
- 28. Estimate the enthalpy (change in energy) of reaction for 2 SO(g) + O2(g) →2 SO2(g) using bond energies. Assume that sulfur in SO2 (g) has an expanded octet. -> Bond Energy (kJ/mol) 498 265 a. 498 kJ/mol c. -498 kJ/mol bь. 731 kJ/mol d. -32KJ/molarrow_forwardCalculate the lattice enthalpy for RbC1. You will need the following information: Species AfH°, kJ/mol Rb(g) RbCl(s) Cl(g) 80.9 - 435.4 121.3 Enthalpy of ionization for Rb(g) is 403.0 kJ/mol; electron attachment enthalpy for Cl(g) is −349.0 kJ/mol. Lattice enthalpy = kJ/molarrow_forwardCarbon naturally occurs in two forms: diamond and graphite. Why do these two forms have very different properties? The key difference is that diamonds have other elements bonded within their structure. The differences are explained by the number of covalent and ionic bonds within each substance. The differences are explained by the density: graphite is very high and diamond is much lower. The differences are explained by how the carbon atoms within each substance are covalently bonded together.arrow_forward
- 16) ( , Using the thermochemical data below calculate the lattice energy for the formation of Na₂O. Na(s) → Na(g) 107.3 kJ/mol Na(g) → Na*(g) + 1 e 495.9 kJ/mol 2 Na(s) + O₂(g) → Na₂O(s) -418 kJ/mol 1/2 O₂(g) → O(g) 249.1 kJ/mol O(g) + 1 e→O(g) -141 kJ/mol -1484.5 kJ/mol O(g) + 1 e0²(g) s) If 115 or pressuarrow_forwardThis thermodynamic cycle describes the formation of an ionic compound MX from a metal element M and nonmetal element X in their standard states. Based of the table (picture): A. What is the lattice enthalpy of MX? (in kJ/mol) B. What is the enthalpy of formation of MX? (in kJ/mol) C. Suppose both the electron affinity of X and the heat of sublimation of M were bigger. Would MX be more or less stable?arrow_forwardWhich one of the following ionic compounds has the smallest lattice formation enthalpy (lattice energy) thus making it the least favorable to form a stable lattice? A) MgF₂ B) Na₂O C) CaO D) LiBrarrow_forward
- This thermodynamic cycle describes the formation of an ionic compound MX from a metal element M and nonmetal element X in their standard states. Based of the table (picture): A. What is the lattice enthalpy of MX2? (in kJ/mol) B. What is the enthalpy of formation of MX2? (in kJ/mol) C. Suppose the electron affinity of X were bigger and the heat of sublimation of M were smaller. Would MX2 be more or less stable? Or would it be impossible to tell without more information?arrow_forwardSuppose a chemist discovers a new metallic element and names it "Xercisium" (Xr). Xr exhibits chemical behaviour similar to an alkaline earth. Xr(s) + Cl2(g) → XrCl2(s) Lattice energy for XrCl2 -2020. kJ/mol First Ionization energy of Xr 500. kJ/mol Second Ionization energy of Xr 950. kJ/mol Electron affinity of Cl -348.7 kJ/mol Bond energy of Cl2 239 kJ/mol Enthalpy of sublimation (atomization) of Xr 200. kJ/mol Use the above data to calculate ΔH°f for Xercisium chloride.arrow_forwardCalculate the lattice energy of magnesium sulfide from the data given below. Mg(s) → Mg(g) ΔH° = 148 kJ/mol Mg(g) → Mg2+(g) + 2e– ΔH° = 2186 kJ/mol S8(s) → 8S(g) ΔH° = 2232 kJ/mol S(g) + 2e- → S2-(g) ΔH° = 450 kJ/mol 8Mg(s) + S8(s) → 8MgS(s) ΔH° = –2744 kJ/mol MgS(s) → Mg2+(g) + S2-(g) ΔH°lattice = ?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning