Chemistry for Engineering Students
4th Edition
ISBN: 9781337398909
Author: Lawrence S. Brown, Tom Holme
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 8, Problem 8.63PAE
Interpretation Introduction
Interpretation:
The
Concept introduction:
The polymers are classified based on the intermolecular forces present in the compound. These are four types. i.e., 1) Elastomers 2) Fibres 3) Thermoplastic polymers 4) Thermosetting polymers
Elastomers are the polymers which contain weakest forces of attractions.
Fibres are the thread forming polymers which contain very strong intermolecular attractions. Hence these polymers are used to make ropes [nylon (6, 6)]
Thermoplastics are the polymers which are linear or slightly branched and have intermediary intermolecular attractions between elastomers and fibres.
Thermosetting
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
Silicon has a face-centred cubic structure with two atoms per lattice point, just like
diamond. At 25°C, a = 543.1 pm. What is the density of silicon?
What is the
Si-Si bond length?
Explain and elaborate in 10 sentences the reason why non crystalline materials does not exhibit allotropy.
What type of bonding would you expect in
Silicon nitride? explain the answer and what
kind of secondary bonding would occur
between polymer chains?
Chapter 8 Solutions
Chemistry for Engineering Students
Ch. 8 - Prob. 1COCh. 8 - • describe the arrangement of atoms in the common...Ch. 8 - • use bind theory to describe bonding in solids.Ch. 8 - Prob. 4COCh. 8 - Prob. 5COCh. 8 - Prob. 6COCh. 8 - Prob. 7COCh. 8 - • explain the connection between intermolecular...Ch. 8 - Prob. 9COCh. 8 - Prob. 10CO
Ch. 8 - Prob. 8.1PAECh. 8 - Why is the C 60form of carbon called...Ch. 8 - Prob. 8.3PAECh. 8 - Prob. 8.4PAECh. 8 - What is the relationship between the structures of...Ch. 8 - Use the web to look up information on nanotubes....Ch. 8 - Prob. 8.7PAECh. 8 - Prob. 8.8PAECh. 8 - Prob. 8.9PAECh. 8 - Prob. 8.10PAECh. 8 - Prob. 8.11PAECh. 8 - Prob. 8.12PAECh. 8 - 8.13 What is the coordination number of atoms in...Ch. 8 - Prob. 8.14PAECh. 8 - Prob. 8.15PAECh. 8 - 8.16 Iridium forms a face-centered cubic lattice,...Ch. 8 - 8.17 Europium forms a body-centered cubic unit...Ch. 8 - 8.18 Manganese has a body-centered cubic unit cell...Ch. 8 - Prob. 8.19PAECh. 8 - 8.20 How many electrons per atom are delocalized...Ch. 8 - Prob. 8.21PAECh. 8 - Prob. 8.22PAECh. 8 - Prob. 8.23PAECh. 8 - 8.24 What is the key difference between metallic...Ch. 8 - 8.25 Draw a depiction of the band structure of a...Ch. 8 - Prob. 8.26PAECh. 8 - Prob. 8.27PAECh. 8 - Prob. 8.28PAECh. 8 - Prob. 8.29PAECh. 8 - Prob. 8.30PAECh. 8 - Prob. 8.31PAECh. 8 - Prob. 8.32PAECh. 8 - Prob. 8.33PAECh. 8 - Suppose that a device is using a 15.0-mg sample of...Ch. 8 - 8.35 What is an instantancous dipole?Ch. 8 - 8.36 Why are dispersion forces attractive?Ch. 8 - 8.37 If a molecule is not very polarizable, how...Ch. 8 - 8.38 What is the relationship between...Ch. 8 - 8.39 Under what circumstances are ion-dipole...Ch. 8 - 8.40 Which of the following compounds would be...Ch. 8 - 8.41 What is the specific feature of N, O, and F...Ch. 8 - Prob. 8.42PAECh. 8 - 8.43 Identify the kinds of intermolecular forces...Ch. 8 - Prob. 8.44PAECh. 8 - 8.45 Describe how interactions between molecules...Ch. 8 - 8.46 What makes a chemical compound volatile?Ch. 8 - 8.47 Answer each of the following questions with...Ch. 8 - 8.48 Why must the vapor pressure of a substance be...Ch. 8 - Prob. 8.49PAECh. 8 - Prob. 8.50PAECh. 8 - 8.51 Suppose that three unknown pure substances...Ch. 8 - 8.52 Rank the following hydrocarbons in order of...Ch. 8 - Prob. 8.53PAECh. 8 - Prob. 8.54PAECh. 8 - Prob. 8.55PAECh. 8 - Prob. 8.56PAECh. 8 - Prob. 8.57PAECh. 8 - Prob. 8.58PAECh. 8 - Prob. 8.59PAECh. 8 - Prob. 8.60PAECh. 8 - 8.61 Distinguish between a block copolymer and a...Ch. 8 - Prob. 8.62PAECh. 8 - Prob. 8.63PAECh. 8 - Prob. 8.64PAECh. 8 - Prob. 8.65PAECh. 8 - 8.66 What structural characteristics are needed...Ch. 8 - Prob. 8.67PAECh. 8 - Prob. 8.68PAECh. 8 - Prob. 8.69PAECh. 8 - Prob. 8.70PAECh. 8 - Prob. 8.71PAECh. 8 - Prob. 8.72PAECh. 8 - Prob. 8.73PAECh. 8 - Prob. 8.74PAECh. 8 - 8.75 Using pentagons, draw arrangements that...Ch. 8 - 8.76 Using circles, draw regular two-dimensional...Ch. 8 - 8.77 What is the difference between a bonding...Ch. 8 - Prob. 8.78PAECh. 8 - 8.79 Most gaseous compounds consist of small...Ch. 8 - 8.80 Why are dipole—dipole forces typically...Ch. 8 - 8.81 Carbon tetrachloride (CCl4) is a liquid at...Ch. 8 - Prob. 8.82PAECh. 8 - Prob. 8.83PAECh. 8 - Prob. 8.84PAECh. 8 - Prob. 8.85PAECh. 8 - Prob. 8.86PAECh. 8 - 8.87 Use the vapor pressure curves illustrated...Ch. 8 - Prob. 8.88PAECh. 8 - 8.89 The following data show the vapor pressure of...Ch. 8 - Prob. 8.90PAECh. 8 - Prob. 8.91PAECh. 8 - Prob. 8.92PAECh. 8 - Prob. 8.93PAECh. 8 - Prob. 8.94PAECh. 8 - Prob. 8.95PAECh. 8 - 8.96 A business manager wants to provide a wider...Ch. 8 - 8.97 The doping of semiconductors can be done with...Ch. 8 - 8.98 If you know the density of material and the...Ch. 8 - Prob. 8.99PAECh. 8 - Prob. 8.100PAECh. 8 - Prob. 8.101PAECh. 8 - Prob. 8.102PAECh. 8 - 8.103 Cryolite (Na3AlF6) is used in refining...Ch. 8 - Prob. 8.104PAECh. 8 - Prob. 8.105PAE
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- What is the relationship between the structures of buckminsterfullerene and carbon nanotubes?arrow_forward<p>Explain why the graphite structure of carbon allows graphite to be used as a lubricant, but the diamond structure of carbon does not.arrow_forwardPolymers do not crystallise easily because:a) they are long chain moleculesb) they contain covalent bondsc) the molecules are interconnected with H-bondingarrow_forward
- 1. The chart below shows three allotropes of carbon. ALLU1HOMIC UHMS O CAKSUN These three forms have 1) the same formula, crystal structure, and properties 2different formulas and crystal structure but same properties 3) different formulas, crystal structure, and properties 4) the same formula, but different crystal structure and properties diamond fallerene graphitearrow_forward8. Clausthalite is a mineral composed of lead(II) selenide. The mineral adopts a NaCl octahedral-type structure. If the density of PbSe is 8.27 g/cm³, calculate the radius of the lead(II) ion. (The radius of selenide ion is given below.)arrow_forward2.4 2.5 The unit cell for Platinum (Pt) has atoms which are located at each of the corners and at the centre of all the unit cell faces. The density and atomic weight of Pt are 21.45 g/cm³ and 195.08 g/mol, respectively. Given that the Avogadro's Number is 6.023 x 1023 atoms/mol, (a) sketch the atomic arrangement on the (010) plane of the unit cell. (b) determine the lattice constant, a of Pt atom. (c) calculate the atomic radius of Pt atom. A sample of BCC iron (Fe) was placed in an X-ray diffractometer using incoming X-rays with a wavelength, λ = 0.1541 nm. Diffraction from the {110} planes was obtained at 20 = 44.704°. Assuming that the order of reflection is 1, calculate: (a) the interplanar spacing of the planes (b) the value for the lattice constant, a for BCC Fearrow_forward
- 4. Why do FCC and HCP have identical atomic packing factors (0.74) if they have different crystal structures?arrow_forwardWhat are the most common types of polymorphism in crystals?arrow_forwardWhat is the molecular formula of the compound represented by the unit cell below? Xenon Fluorinearrow_forward
- Q3/ Do the atoms of silicon dioxide are aranged in crystalline or amorphous state? If so, what is (are) the reason(s) beyond this phenomena?arrow_forwardIn terms of electron energy band structure, discuss the differences in optically transparent, translucent and opaque materials.arrow_forwardThe density of platinum is 21.45 g/cm3. It crystallizes in a fcc lattice. Calculate its metallic radius.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
Chemistry for Engineering StudentsChemistryISBN:9781285199023Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781285199023
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning