Videos
(a)
Interpretation:
The number of inner, outer and valence electrons present in an
Concept introduction:
The inner electrons are the electrons that are present in the inner shells of the atom. These are also known as core electrons. These are tightly bound to the nucleus and donot participate in the bonding.
The outer electrons are the electrons that are present in the outermost shell or the highest principle energy level of the atom. These may or may not be valence electrons.
The valence electrons are the electrons that are present in the outermost shell or higher energy level of an atom. They participate in the formation of
(b)
Interpretation:
The number of inner, outer and valence electrons present in
Concept introduction:
The inner electrons are the electrons that are present in the inner shells of the atom. These are also known as core electrons. These are tightly bound to the nucleus and donot participate in the bonding.
The outer electrons are the electrons that are present in the outermost shell or the highest principle energy level of the atom. These may or may not be valence electrons.
The valence electrons are the electrons that are present in the outermost shell or higher energy level of an atom. They participate in the formation of chemical bonding and also determine the chemical properties of the atom.
(c)
Interpretation:
The number of inner, outer and valence electrons present in
Concept introduction:
The inner electrons are the electrons that are present in the inner shells of the atom. These are also known as core electrons. These are tightly bound to the nucleus and donot participate in the bonding.
The outer electrons are the electrons that are present in the outermost shell or the highest principle energy level of the atom. These may or may not be valence electrons.
The valence electrons are the electrons that are present in the outermost shell or higher energy level of an atom. They participate in the formation of chemical bonding and also determine the chemical properties of the atom.
(d)
Interpretation:
The number of inner, outer and valence electrons present in
Concept introduction:
The inner electrons are the electrons that are present in the inner shells of the atom. These are also known as core electrons. These are tightly bound to the nucleus and donot participate in the bonding.
The outer electrons are the electrons that are present in the outermost shell or the highest principle energy level of the atom. These may or may not be valence electrons.
The valence electrons are the electrons that are present in the outermost shell or higher energy level of an atom. They participate in the formation of chemical bonding and also determine the chemical properties of the atom.
(e)
Interpretation:
The number of inner, outer and valence electrons present in
Concept introduction:
The inner electrons are the electrons that are present in the inner shells of the atom. These are also known as core electrons. These are tightly bound to the nucleus and donot participate in the bonding.
The outer electrons are the electrons that are present in the outermost shell or the highest principle energy level of the atom. These may or may not be valence electrons.
The valence electrons are the electrons that are present in the outermost shell or higher energy level of an atom. They participate in the formation of chemical bonding and also determine the chemical properties of the atom.
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Chapter 8 Solutions
CHEMISTRY: THE MOLECULAR NATURE OF MATTE
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- 3. Provide the missing compounds or reagents. 1. H,NNH КОН 4 EN MN. 1. HBUCK = 8 хно Panely prowseful kanti-chuprccant fad, winddively, can lead to the crading of deduc din-willed, tica, The that chemooices in redimi Грин. " like (for alongan Ridovi MN نيا . 2. Cl -BuO 1. NUH 2.A A -BuOK THE CF,00,H Ex 5)arrow_forward2. Write a complete mechanism for the reaction shown below. NaOCH LOCH₁ O₂N NO2 CH₂OH, 20 °C O₂N NO2arrow_forward4. Propose a synthesis of the target molecules from the respective starting materials. a) b) LUCH C Br OHarrow_forward
- The following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forward
- The following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forwardSelect all possible products from the following reaction: NaOH H₂O a) b) ОН HO O HO HO e) ОН f) O HO g) h) + OHarrow_forward3. Draw diagrams to represent the conjugation in these molecules. Draw two types of diagram: a. Show curly arrows linking at least two different ways of representing the molecule b. Indicate with dotted lines and partial charges (where necessary) the partial double bond (and charge) distribution H₂N* H₂N -NH2arrow_forward
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