
Concept explainers
Interpretation:
The wrong point in the given Lewis structures is to be stated, and the correct Lewis structure of the molecule is to be drawn.
Concept Introduction:
Lewis structure is a representation of the bonding and non-bonding electron pairs present in the outermost shell of all atoms present in the molecule.
The number of bonds formed by an atom in the molecule is determined by the valence electrons pairs.

Answer to Problem 50QP
Solution:
a)
The double bond is present between the carbon and nitrogen atoms.
The correct Lewis structure is as follows:
b)
The double bond is present between the carbon and hydrogen atoms.
The correct Lewis structure is as follows:
c)
A single bond is present between the
The correct Lewis structure is as follows:
d)
The lone pair of electrons on boron.
The correct Lewis structure is as follows:
e)
The double bond between the oxygen and fluorine atoms.
The correct Lewis structure is as follows:
f)
The single bond between the carbon and oxygen atoms.
The correct Lewis structure is as follows:
g)
The lone pair of electrons of the nitrogen atom is missing.
The correct Lewis structure is as follows:
Explanation of Solution
a)
The given Lewis structure is as follows:
The electronic configurations of hydrogen, carbon, and nitrogen in
Carbon has four electrons in its outermost shell and requires four electrons to complete its outermost shell of electrons, while nitrogen requires three electrons to complete its octet and hydrogen requires one electron to obtain its fully-filled electronic configuration. Therefore, the Lewis structure of
The correct Lewis structure of
Hence, the given Lewis structure of
b)
The given Lewis structure is as follows:
The electronic configurations of carbon and hydrogen in
The carbon atom contains four electrons in its outermost shell and the hydrogen atom contains one valence electron in its
The correct Lewis structure of
Hence, the given Lewis structure of
c)
The given Lewis structure is as follows:
The electronic configurations of tin and oxygen in
A carbon atom has a tendency to form four bonds because of the presence of four valence electrons in its outermost shell, while oxygen has a tendency to form two bonds due to the presence of two electrons in its outermost shell. The Lewis structure of
The correct Lewis structure of
Hence, the given Lewis structure of
d)
The given Lewis structure is as follows:
The electronic configurations of boron and fluorine in
The boron atom contains three electrons in its outermost shell and the fluorine atom contains five electrons in its
The Lewis structure of
Hence, the given Lewis structure of
e)
The given Lewis structure is as follows:
The electronic configurations of hydrogen, oxygen, and fluorine in
Hydrogen has a tendency to form one bond because of the presence of one electron in its outermost shell, fluorine has a tendency to form one bond because of the presence of five electrons in its
The correct Lewis structure of
Hence, the given Lewis structure of
f)
The given Lewis structure is as follows:
The electronic configurations of fluorine, carbon, oxygen, and hydrogen in
The fluorine atom has a tendency to form one bond because of the presence of five valence electrons in its
Hence, the given Lewis structure of
g)
The given Lewis structure is,
The electronic configurations of nitrogen and chlorine in
The nitrogen atom contains three valence electrons in its
The correct Lewis structure of
Hence, the given Lewis structure of
Want to see more full solutions like this?
Chapter 8 Solutions
CHEMISTRY >CUSTOM<
- Synthesize 2-Hydroxy-2-phenylacetonitrile from phenylmethanol using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardSynthesize N-Methylcyclohexylamine from cyclohexanol using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardSynthesize N-Methylcyclohexylamine from cyclohexanol using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forward
- If possible, please provide the formula of the compound 3,3-dimethylbut-2-enal.arrow_forwardSynthesize 1,4-dibromobenzene from acetanilide (N-phenylacetamide) using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardIndicate the products obtained by mixing (3-oxo-3-phenylpropyl)triphenylphosphonium bromide with sodium hydride.arrow_forward
- We mix N-ethyl-2-hexanamine with excess methyl iodide and followed by heating with aqueous Ag2O. Indicate the major products obtained.arrow_forwardIndicate the products obtained by mixing acetophenone with iodine and NaOH.arrow_forwardIndicate the products obtained by mixing 2-Propanone and ethyllithium and performing a subsequent acid hydrolysis.arrow_forward
- Indicate the products obtained if (E)-2-butenal and 3-oxo-butanenitrile are mixed with sodium ethoxide in ethanol.arrow_forwardQuestion 3 (4 points), Draw a full arrow-pushing mechanism for the following reaction Please draw all structures clearly. Note that this intramolecular cyclization is analogous to the mechanism for halohydrin formation. COH Br + HBr Brarrow_forwardIndicate the products obtained if 2,2-dimethylpropanal and acetaldehyde are mixed with sodium ethoxide in ethanol.arrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoChemical Principles in the LaboratoryChemistryISBN:9781305264434Author:Emil Slowinski, Wayne C. Wolsey, Robert RossiPublisher:Brooks ColeChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning




