Explanation Write the expression tensile load per bolt. P = p g × A s (I) Here, tensile load per bolt is P , pressure is p g and cross section area of sealing is A s . Write the expression for cross section area of sealing. A s = π 4 D 2 (II) Here, area is A s and sealing diameter is D . Write the expression for grip length. l = A + B (III) Here, grip length is l , length of upper portion of bolt is A and the length of lower portion of the bolt is B . Write the expression for length of bolt. L = l + H (IV) Here length of bolt is L , grip length is l and the height of nut is H . Write the expression for threaded length for metric series d ≤ 48 mm . L t = 2 d + 0.25 in (V) Here threaded length is L t and fastener diameter is d . Write the expression for area of unthreaded portion. A d = π 4 d 2 (VI) Here, the area of unthreaded portion is A d and the fastener diameter is d . Write the expression for length of unthreaded portion in grip. l d = L − L T (VII) Here, the length of unthreaded portion in grip is l d . Write the expression for length of threaded portion in grip. l t = l − l d (VIII) Here, length of threaded portion in grip is l t . Write the expression for bolt stiffness. k b = A d A t E A d l t + A t l d (IX) Here, bolt stiffness is k b . Write the expression for stiffness of members. k m = A exp ( B d l ) E D (X) Here, member stiffness is k m . Write the expression for equivalent member stiffness. k m e = 1 1 2 k s e + 1 2 k m s (XI) Here, the member stiffness is k m , member stiffness for steel is k m s and member stiffness for cast iron is k s e Write the expression for joint stiffness constant. C = k b k b + k m e (XII) Here, joint stiffness constant is C . Write the expression for preload. F i = 0.75 S p A t (XIII) Here, preload is F i , minimum proof strength is S p and tensile stress area is A t . Write the expression for maximum pressure. P max = P N (XIV) Here, maximum pressure is P max , pressure is P and number of bolt is N . Write the expression for load factor n L = S p A t − F i C ( P max ) (XV) Here, load factor is n L . Write the expression for yielding factor of safety. n P = S p A t C ( P max ) + F i (XVI) Here, yielding factor of safety is n P . Write the expression for load factor guarding against joint separation. n o = F i ( P max ) ( 1 − C ) (XVII) Here, load factor guarding against joint is n o . Conclusion: Substitute 4.25 in for D in Equation (II). A s = π 4 ( 4.25 in ) 2 = 14.186 lbf Substitute 14.186 lbf for A s and 1500 psi for p g in Equation (I). P = 1500 psi × ( 14.186 lbf ) = 21279.38 lbf Substitute 1 2 in for A and 5 8 in for B in Equation (III). l = 1 2 in + 5 8 in = 1.125 in Refer to table A-31, “Dimensions of hexagonal nuts” to obtain the diameter as 1 2 in and nut thickness as 7 16 in . Substitute 1.125 in for l and 7 16 in for H in Equation (IV). L = ( 1.125 in ) + ( 7 16 in ) = 1.5625 in ≈ 1.6 in Substitute 0.5 in for d in Equation (V). L t = 2 ( 0.5 in ) + 0.25 in = 1.25 in Substitute 0.5 in for d in Equation (VI). A d = π 4 ( 0.5 in ) 2 = ( 0.78539 ) ( 0.5 in ) 2 = 0.1963 in 2 Substitute 1.6 in for L and 1.25 in for L T in Equation (VII). l d = 1.6 in − 1

Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)

10th Edition

ISBN: 9780073398204

Author: Richard G Budynas, Keith J Nisbett

Publisher: McGraw-Hill Education

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Chapter 8, Problem 42P

To determine

The yielding factor of safety.

The load factor.

The joint separation factor.

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Chapter 8, Problem 41P

Chapter 8, Problem 43P

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0 = 6 a = 25 t = 3 Y b = 30 x

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Chapter 8 Solutions

Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)

Ch. 8 - A power screw is 25 mm in diameter and has a...Ch. 8 - Using the information in the footnote of Table...Ch. 8 - Show that for zero collar friction the efficiency...Ch. 8 - A single-threaded power screw is 25 mm in diameter...Ch. 8 - The machine shown in the figure can be used for a...Ch. 8 - The press shown for Prob. 8-5 has a rated load of...Ch. 8 - For the screw clamp shown, a force is applied at...Ch. 8 - The C clamp shown in the figure for Prob. 8-7 uses...Ch. 8 - Find the power required to drive a 1.5-in power...Ch. 8 - A single square-thread power screw has an input...

Ch. 8 - Prob. 11P Ch. 8 - An M14 2 hex-head bolt with a nut is used to...Ch. 8 - Prob. 13P Ch. 8 - A 2-in steel plate and a 1-in cast-iron plate are...Ch. 8 - Repeat Prob. 8-14 with the addition of one 12 N...Ch. 8 - A 2-in steel plate and a 1-in cast-iron plate are...Ch. 8 - Two identical aluminum plates are each 2 in thick,...Ch. 8 - Prob. 18P Ch. 8 - A 30-mm thick AISI 1020 steel plate is sandwiched...Ch. 8 - Prob. 20P Ch. 8 - Prob. 21P Ch. 8 - Prob. 22P Ch. 8 - A 2-in steel plate and a 1-in cast-iron plate are...Ch. 8 - An aluminum bracket with a 12-in thick flange is...Ch. 8 - An M14 2 hex-head bolt with a nut is used to...Ch. 8 - A 34 in-16 UNF series SAE grade 5 bolt has a 34-in...Ch. 8 - From your experience with Prob. 8-26, generalize...Ch. 8 - Prob. 28P Ch. 8 - Prob. 29P Ch. 8 - Prob. 30P Ch. 8 - For a bolted assembly with eight bolts, the...Ch. 8 - Prob. 32P Ch. 8 - 8-33 to 8-36 The figure illustrates the...Ch. 8 - 8-33 to 8-36 The figure illustrates the...Ch. 8 - 8-33 to 8-36 The figure illustrates the...Ch. 8 - 8-33 to 8-36 The figure illustrates the...Ch. 8 - Prob. 37P Ch. 8 - Prob. 38P Ch. 8 - 837 to 840 Repeat the requirements for the problem...Ch. 8 - Prob. 40P Ch. 8 - 841 to 844 For the pressure vessel defined in the...Ch. 8 - Prob. 42P Ch. 8 - Prob. 43P Ch. 8 - Prob. 44P Ch. 8 - Bolts distributed about a bolt circle are often...Ch. 8 - The figure shows a cast-iron bearing block that is...Ch. 8 - Prob. 47P Ch. 8 - Prob. 48P Ch. 8 - Prob. 49P Ch. 8 - Prob. 50P Ch. 8 - 851 to 854 For the pressure cylinder defined in...Ch. 8 - Prob. 52P Ch. 8 - 851 to 854 For the pressure cylinder defined in...Ch. 8 - 851 to 854 For the pressure cylinder defined in...Ch. 8 - 855 to 858 For the pressure cylinder defined in...Ch. 8 - 855 to 858 For the pressure cylinder defined in...Ch. 8 - 855 to 858 For the pressure cylinder defined in...Ch. 8 - For the pressure cylinder defined in the problem...Ch. 8 - A 1-in-diameter hot-rolled AISI 1144 steel rod is...Ch. 8 - The section of the sealed joint shown in the...Ch. 8 - Prob. 61P Ch. 8 - Prob. 62P Ch. 8 - Prob. 63P Ch. 8 - Prob. 64P Ch. 8 - Using the Goodman fatigue criterion, repeat Prob....Ch. 8 - The figure shows a bolted lap joint that uses SAE...Ch. 8 - Prob. 67P Ch. 8 - A bolted lap joint using ISO class 5.8 bolts and...Ch. 8 - Prob. 69P Ch. 8 - The figure shows a connection that employs three...Ch. 8 - A beam is made up by bolting together two cold...Ch. 8 - Prob. 72P Ch. 8 - Prob. 73P Ch. 8 - Prob. 74P Ch. 8 - A vertical channel 152 76 (see Table A7) has a...Ch. 8 - The cantilever bracket is bolted to a column with...Ch. 8 - Prob. 77P Ch. 8 - The figure shows a welded fitting which has been...Ch. 8 - Prob. 79P Ch. 8 - Prob. 80P Ch. 8 - Prob. 81P

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The yielding factor of safety. The load factor. The joint separation factor.

Solution Summary: The author explains the yielding factor of safety, the load factor, and the joint separation factor.