Numerical Methods for Engineers
Numerical Methods for Engineers
7th Edition
ISBN: 9780073397924
Author: Steven C. Chapra Dr., Raymond P. Canale
Publisher: McGraw-Hill Education
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Chapter 8, Problem 19P

The displacement of a structure is defined by the following equation for a damped oscillation:

y = 8 e k t  cos  ω t

where k = 0.5  and  ω = 3 .

(a) Use the graphical method to make an initial estimate of the time required for the displacement to decrease to 4.

(b) Use the Newton-Raphson method to determine the root to ε s = 0.01 % .

(c) Use the secant method to determine the root to ε s = 0.01 % .

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Problem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/s
Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4
Problem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…

Chapter 8 Solutions

Numerical Methods for Engineers

Ch. 8 - 8.11 The operation of a constant density plug flow...Ch. 8 - 8.12 The Ergun equation, shown below, is used to...Ch. 8 - The pressure drop in a section of pipe can be...Ch. 8 - 8.14 In structural engineering, the secant formula...Ch. 8 - 8.15 In environmental engineering (a specialty...Ch. 8 - 8.16 The concentration of pollutant bacteria c in...Ch. 8 - A catenary cable is one that is hung between two...Ch. 8 - 8.18 Figure P8.18a shows a uniform beam subject to...Ch. 8 - 8.19 The displacement of a structure is defined by...Ch. 8 - 8.20 The Manning equation can be written for a...Ch. 8 - In ocean engineering, the equation for a reflected...Ch. 8 - 8.22 You buy a $20,000 piece of equipment for...Ch. 8 - Many fields of engineering require accurate...Ch. 8 - 8.24 A simply supported beam is loaded as shown in...Ch. 8 - 8.25 Using the simply supported beam from Prob....Ch. 8 - Using the simply supported beam from Prob. 8.24,...Ch. 8 - Using the simply supported beam from Prob. 8.24,...Ch. 8 - 8.28 Although we did not mention it in Sec. 8.2,...Ch. 8 - 8.29 Perform the same computation as in Sec. 8.3,...Ch. 8 - An oscillating current in an electric circuit is...Ch. 8 - Prob. 31PCh. 8 - 8.32 A total charge Q is uniformly distributed...Ch. 8 - 8.33 Figure P8.33 shows a circuit with a resistor,...Ch. 8 - Beyond the Colebrook equation, other...Ch. 8 - Real mechanical systems may involve the deflection...Ch. 8 - Mechanical engineers, as well as most other...Ch. 8 - Aerospace engineers sometimes compute the...Ch. 8 - The general form for a three-dimensional stress...Ch. 8 - The upward velocity of a rocket can be computed by...Ch. 8 - The phase angle between the forced vibration...Ch. 8 - Two fluids at different temperatures enter a mixer...Ch. 8 - A compressor is operating at compression ratio Rc...Ch. 8 - In the thermos shown in Fig. P8.43, the innermost...Ch. 8 - 8.44 Figure P8.44 shows three reservoirs connected...Ch. 8 - A fluid is pumped into the network of pipes...Ch. 8 - 8.46 Repeat Prob. 8.45, but incorporate the fact...Ch. 8 - The space shuttle, at lift-off from the launch...Ch. 8 - 8.48 Determining the velocity of particles...
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