(a)
The partial fraction for the equation
(a)

Answer to Problem 60E
The partial fraction equation will be
Explanation of Solution
Given:
The given equation is
Formula used:
Substitution method is used.
Calculation:
The Partial fraction of the equation is
Comparing both side
Substituting both equations we get
So, the partial equation be
Conclusion:
The partial fraction equation will be
(b)
To calculate:The values of
(b)

Answer to Problem 60E
The values are
Explanation of Solution
Given:
The given equation is
Formula used:
Substitution method is used
Calculation:
The partial fraction in difference form is
Hence,
Conclusion:
The values are
(c)
To sketch: The graph for the values of
(c)

Answer to Problem 60E
Explanation of Solution
Given:
The given equation is
Formula used:
Substitution method is used
Calculation:
The Graph of both
Here, red line is Y max and blue line is Y min.
Conclusion:
The values of
(d)
To calculate: The maximum and minimum frequencies for the relative load.
(d)

Answer to Problem 60E
The maximum and minimum frequencies are
Explanation of Solution
Given:
The given equation is
Formula used:
Substitution method is used.
Calculation:
Relative load is 0.5.
Now,
Conclusion:
The maximum and minimum frequencies are
Chapter 7 Solutions
EBK PRECALCULUS W/LIMITS
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