(a)
Interpretation: The product of given two-step sequence is to be drawn.
Concept introduction: The replacement or substitution of one
(b)
Interpretation: The product of given two-step sequence is to be drawn.
Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron rich chemical species that contains negative charge or lone pair of electrons are known as a nucleophile. In a nucleophilic substitution reaction, nucleophile takes the position of leaving group by attacking the electron deficient carbon atom.
(c)
Interpretation: The product of given two-step sequence is to be drawn.
Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron rich chemical species that contains negative charge or lone pair of electrons are known as a nucleophile. In a nucleophilic substitution reaction, nucleophile takes the position of leaving group by attacking the electron deficient carbon atom.
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ORGANIC CHEMISTRY
- 3) Draw the structures of the major organic product(s) for the following reactions. HI in CH₂Cl₂ 3 excess Cl₂ in H₂O H₂SO4 in H₂O (Two products) Br-Cl in THF 1) BH3 2) alkaline H₂O₂ OSO4 + HOOHarrow_forwardb) Listed below are several hypothetical nucleophilic substitution reactions. None is synthetically useful because the product indicated is not formed at an appreciable rate. In each case provide an explanation for the failure of the reaction to take place as indicated. OMe HO + OMe + OH HO + CH; OHarrow_forwardBr Brz CH3 CH3 H3C CH2CI2 H3C Br Electrophilic addition of bromine, Br2; to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl). In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br: :Br: .CH3 H3C H3C CH3 Br:arrow_forward
- Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CI + H₂N • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. OH • Do not include counter-ions, e.g., Na+, I¯, in your answer. • In cases where there is more than one answer, just draw one.arrow_forwardplease help me with all parts of this question, it is a single question with multiple subpartsarrow_forward10. Why do aldehydes undergo nucleophilic addition reactions (rxns from Unit 10) while esters undergo nucleophilic acyl substitution (rxns from Unit 11) reactions? A) The carbonyl carbon of an ester is more electrophilic than that of an aldehyde. B) Aldehydes are more sterically hindered than esters. C) Once the nucleophile adds to an aldehyde, the tetrahedral intermediate is too sterically hindered to eliminate one of the attached groups. D) The ester carbonyl carbon is sp3 hybridized while the aldehyde carbonyl carbon is sp2 hybridized. E) Once the nucleophile adds to an aldehyde, neither H- nor R- can be eliminated since they are strongly basic.arrow_forward
- Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. You do not have to consider stereochemistry. Include all valence lone pairs in your answer. Do not include counter-ions, e.g., Na+, I-, in your answer. In cases where there is more than one answer, just draw one.arrow_forwardAcyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. You do not have to consider stereochemistry. Include all valence lone pairs in your answer. Do not include counter-ions, e.g., Na+, I-, in your answer. In cases where there is more than one answer, just draw one.arrow_forwardCan you answer both please, thank you!arrow_forward
- Draw curved arrows to show the movement of electrons in this step of the mechanism.arrow_forwardThe question is: "Draw the curved arrow mechanism for the reaction between pentan-2-one and (CH3)3O– in t-butanol to form an enolate. Draw all electrons and charges on both resonance structures. Then answer the question about the reaction." I got the initial arrows correct, but am not entirely sure what the carbanion intermediate would look like and then what the curved arrows would be to convert it to its final oxanion formarrow_forwardDraw the structure of the product of the Michael reaction between propenamide and diethyl malonatearrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning