Chapter 7, Problem 7.22E

Interpretation Introduction

(a)

Interpretation:

The molarity of a sample of solid $\text{KBr}$ weighing $11.9\text{g}$ on dissolving in enough distilled water to give $200.\text{mL}$ of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume $\left(\text{\%}\text{w}/\text{v}\right)$, percent volume by volume $\left(\text{\%}\text{v}/\text{v}\right)$ and molarity $\left(\text{M}\right)$. When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight $\left(\text{\%}\text{w}/\text{w}\right)$.

Interpretation Introduction

(b)

Interpretation:

The molarity of $\text{14}\text{.2-g}$ sample of solid ${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}$ dissolved in enough water to give $500.\text{mL}$ of solution is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume $\left(\text{\%}\text{w}/\text{v}\right)$, percent volume by volume $\left(\text{\%}\text{v}/\text{v}\right)$ and molarity $\left(\text{M}\right)$. When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight $\left(\text{\%}\text{w}/\text{w}\right)$.

Interpretation Introduction

(c)

Interpretation:

The molarity of a $\text{10}\text{.0-mL}$ sample of solution that was evaporated to dryness and $0.29\text{g}$ of ${\text{Li}}_{\text{2}}{\text{SO}}_{\text{4}}$ was left is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume $\left(\text{\%}\text{w}/\text{v}\right)$, percent volume by volume $\left(\text{\%}\text{v}/\text{v}\right)$ and molarity $\left(\text{M}\right)$. When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight $\left(\text{\%}\text{w}/\text{w}\right)$.