General Chemistry
4th Edition
ISBN: 9781891389603
Author: Donald A. McQuarrie, Peter A. Rock, Ethan B. Gallogly
Publisher: University Science Books
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Chapter 7, Problem 7.1P
Interpretation Introduction
Interpretation:
The Lewis structure of
Concept Introduction:
Lewis Structure: A Lewis structure shows a covalent bond as pair of electrons shared between two atoms.
Procedure to write Lewis formulas:
- 1) The symbols of the atoms that are bonded together in the molecule next to one another are arranged.
- 2) The total number of valence electrons in the molecule is calculated by adding the number of valence electrons for all the atoms in the molecules. If the species is an ion, then the charge of ion into account by adding electrons, if it is a negative ion or subtracting electrons if it is a positive ion.
- 3) A two-electron covalent bond is represented by placing a line between the atoms, which are assumed to be bonded to each other.
- 4) The remaining valence electrons as lone pairs about each atom are arranged so that the octet rule is satisfied for each other.
Expert Solution & Answer
Explanation of Solution
The total number of valence electrons is,
Number of valence electrons in hydrogen=
Number of valence electrons in oxygen=
The total number of valence electrons is 14 electrons.
The Lewis formula of hydrogen peroxide is,
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22.22 For each compound, indicate which group on the ring is more strongly activating and then
draw a structural formula of the major product formed by nitration of the compound.
Br
CHO
(a)
CH3
(b)
(c)
CHO
CH3
SO₂H
(d)
☑
OCHS
NO₂
(e)
(f)
CO₂H
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NHCOCH,
(h)
CHS
22.23 The following molecules each contain two aromatic rings.
(b)
000-100-
H3C
(a)
(c)
Which ring in each undergoes electrophilic aromatic substitution more readily? Draw
the major product formed on nitration.
Chapter 7 Solutions
General Chemistry
Ch. 7 - Prob. 7.1PCh. 7 - Prob. 7.2PCh. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10P
Ch. 7 - Prob. 7.11PCh. 7 - Prob. 7.12PCh. 7 - Prob. 7.13PCh. 7 - Prob. 7.14PCh. 7 - Prob. 7.15PCh. 7 - Prob. 7.16PCh. 7 - Prob. 7.17PCh. 7 - Prob. 7.18PCh. 7 - Prob. 7.19PCh. 7 - Prob. 7.20PCh. 7 - Prob. 7.21PCh. 7 - Prob. 7.22PCh. 7 - Prob. 7.23PCh. 7 - Prob. 7.24PCh. 7 - Prob. 7.25PCh. 7 - Prob. 7.26PCh. 7 - Prob. 7.27PCh. 7 - Prob. 7.28PCh. 7 - Prob. 7.29PCh. 7 - Prob. 7.30PCh. 7 - Prob. 7.31PCh. 7 - Prob. 7.32PCh. 7 - Prob. 7.33PCh. 7 - Prob. 7.34PCh. 7 - Prob. 7.35PCh. 7 - Prob. 7.36PCh. 7 - Prob. 7.37PCh. 7 - Prob. 7.38PCh. 7 - Prob. 7.39PCh. 7 - Prob. 7.40PCh. 7 - Prob. 7.41PCh. 7 - Prob. 7.42PCh. 7 - Prob. 7.43PCh. 7 - Prob. 7.44PCh. 7 - Prob. 7.45PCh. 7 - Prob. 7.46PCh. 7 - Prob. 7.47PCh. 7 - Prob. 7.48PCh. 7 - Prob. 7.49PCh. 7 - Prob. 7.50PCh. 7 - Prob. 7.51PCh. 7 - Prob. 7.52PCh. 7 - Prob. 7.53PCh. 7 - Prob. 7.54PCh. 7 - Prob. 7.55PCh. 7 - Prob. 7.56PCh. 7 - Prob. 7.57PCh. 7 - Prob. 7.58PCh. 7 - Prob. 7.59PCh. 7 - Prob. 7.60PCh. 7 - Prob. 7.61PCh. 7 - Prob. 7.62PCh. 7 - Prob. 7.63PCh. 7 - Prob. 7.64PCh. 7 - Prob. 7.65P
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