Chapter 7, Problem 7.108QP

Interpretation Introduction

Interpretation:

The number of photons of the energy for light of $\text{600 nm}$ wavelength in which the energy corresponds to radiant energy incident on the retina of a human eye that can detect light at $\text{4}{\text{.0 × 10}}^{-\text{17}}\text{ J}$ should be calculated using the relation between speed, wavelength and frequency of a wave and Planck’s quantum theory.

Concept Introduction:

The mathematical equation of various characteristics of light wave is

$\text{c = νλ}$

Where,

C is speed of light ($\text{3}{\text{.00 × 10}}^{\text{8}}\text{ m/s}$).

$\text{ν}$ is the frequency

$\text{λ}$ is wavelength.

The energy of each photon is given as

$\text{E}\text{=}\text{hν}$

Where,

h is Planck’s constant ($\text{6}\text{.63}\text{×}{\text{10}}^{\text{-34}}\text{J}\text{.s}$ ) which relates energy and frequency.

$\text{ν}$ is the frequency.

E is energy of light particle