Interpretation:
The inadequacies of Bohr’s theory should be explained using the concept of Bohr’s theory.
Concept Introduction:
The emission of radiation given by an energized hydrogen atom to the electron falling from a higher-energy orbit to a lower orbit give a quantum of energy in the form of light. Based on electrostatic interaction and law of motion, Bohr derived the following equation.
where
The electrons are excited thermally when the light is used by an object. As a result, an emission spectrum comes. Line spectra consist of light only at specific, discrete wavelengths. In emission, the electron returns to a lower energy state from
This transition results in the photon’s emission with frequency
When
Bohr’s theory of the hydrogen atom describes an atom as a small, positively charged nucleus with electrons travelling around it in circular orbits. It explains the appearance of an emission spectrum because the “orbits” available for the electrons to occupy in their excited states are quantized. The resulting transition emits a specific wavelength of light because the energy of the “orbit” is quantized.
Figure.1
Visible line emission spectrum of hydrogen
The emission spectrum of hydrogen shows a wide range of wavelengths from the infrared to the ultraviolet region. The given table lists the series of transitions in the hydrogen spectrum, each with a different value of
Series | Spectrum region | ||
Lyman | 1 | 2, 3, 4, ... | Ultraviolet |
Balmer | 2 | 3, 4, 5, ... | Visible and Ultraviolet |
Paschen | 3 | 4, 5, 6, ... | Infrared |
Brackett | 4 | 5, 6, 7, ... | Infrared |
The given figure shows transitions associated with spectral lines in each of the emission series. Each horizontal line represents one of the allowed energy levels for the electron in a hydrogen atom. The energy levels are labeled with their
Figure.2
Energy levels in the hydrogen atom and the various emission series.
Each series ends at a different value of

Want to see the full answer?
Check out a sample textbook solution
Chapter 7 Solutions
EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
- b. H3C CH3 1. 2. H3O+ H3C MgBr H3Carrow_forwardPredict the major products of this reaction: excess H+ NaOH ? A Note that the first reactant is used in excess, that is, there is much more of the first reactant than the second. If there won't be any products, just check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privarrow_forward1. For each of the reaction "railroads" below, you are either asked to give the structure(s) of the starting material(s) or product(s), or provide reagents/conditions to accomplish the transformation, as indicated by the boxes. a. NaOMe H+ .CO,H HO₂C MeOH (excess) MeOH H3C Br يع CH3 1. LiAlH4 2. H3O+ 3. PBг3 H3C 1. Et-Li 2. H3O+ -CO₂Me -CO₂Me OH CH3 CH3 ল CH3arrow_forward
- Predict the intermediate 1 and final product 2 of this organic reaction: NaOMe ག1, ད།་, - + H You can draw 1 and 2 in any arrangement you like. 2 work up Note: if either 1 or 2 consists of a pair of enantiomers, just draw one structure using line bonds instead of 3D (dash and wedge) bonds at the chiral center. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Parrow_forwardWhat is the total energy cost associated with the compound below adopting the shown conformation? CH3 HH DH CH3arrow_forwardΗΝ, Draw Final Product C cyclohexanone pH 4-5 Edit Enamine H3O+ CH3CH2Br THF, reflux H Edit Iminium Ionarrow_forward
- How many hydrogen atoms are connected to the indicated carbon atom?arrow_forwardIdentify the compound with the longest carbon - nitrogen bond. O CH3CH2CH=NH O CH3CH2NH2 CH3CH2C=N CH3CH=NCH 3 The length of all the carbon-nitrogen bonds are the samearrow_forwardIdentify any polar covalent bonds in epichlorohydrin with S+ and 8- symbols in the appropriate locations. Choose the correct answer below. Η H's+ 6Η Η Η Η Η Ηδ Η Ο Ο HH +Η Η +Η Η Η -8+ CIarrow_forward
- H H:O::::H H H HH H::O:D:D:H HH HH H:O:D:D:H .. HH H:O:D:D:H H H Select the correct Lewis dot structure for the following compound: CH3CH2OHarrow_forwardRank the following compounds in order of decreasing boiling point. ннннн -С-С-Н . н-с- ННННН H ΗΤΗ НННН TTTĪ н-с-с-с-с-о-н НННН НН C' Н н-с-с-с-с-н НН || Ш НННН H-C-C-C-C-N-H ННННН IVarrow_forwardRank the following compounds in order of decreasing dipole moment. |>||>||| ||>|||>| |>|||>|| |||>||>| O ||>>||| H F H F H c=c || H c=c F F IIIarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





