Interpretation:
The reason corresponding to the formation of products in each of the given reactions is to be explained.
Concept Introduction:
▸ The molecules which are non-superimposable or not identical with their mirror images are known as chiral molecules.
▸ A pair of two mirror images which are non-identical is known as enantiomers which are optically active.
▸ The objects or molecules which are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.
▸ The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive.
▸ The stereoisomers which are non-superimposable on each other and not mirror images of each other are known as diastereomers.
▸ Chiral molecules are capable of rotating plane polarized light
▸ The molecules which are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light.
▸ Priority is given to all the four group attached to the chirality center.
▸ Priority is assigned on the basis of the
▸ If priority cannot be assigned according to
▸ After assigning priority to the four groups, rotate the molecule such that fourth priority group is away from the observer.
▸ Now, move from a to b to c; if the direction is clockwise, then the chiral center designated as
▸
▸ Z-isomers have the high priority group on the same side of the double bond whereas E-isomers have the high priority group on the opposite side of the double bond.
▸ In
▸ In alkenes, if the higher priority group on both the carbon is on the opposite side, configuration is termed as E-configuration.
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Organic Chemistry
- Compounds X and Y are both C7H15Cl products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C7H₁4 alkene. Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C7H15l products; in this reaction Y reacts faster than X. What is the structure of X? • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. . Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. наarrow_forwardReaction of this bicycloalkene with bromine in carbon tetrachloride gives a trans dibro- mide. In both (a) and (b), the bromine atoms are trans to each other. However, only one of these products is formed. CH3 CH3 CH3 Br Br CH,Cl, + Br2 or Br Br (a) (b) Which trans dibromide is formed? How do you account for the fact that it is formed to the exclusion of the other trans dibromide?arrow_forwardCompound A Br₂, H₂O Compound B (C8H15BrO) + enantiomer CH₂O O Compound C + enantiomer Draw the structure of Compound B (watch out for stereochemistry), and mechanisms for its formation from Compound A, and its conversion to Compound C.arrow_forward
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