![Introductory Chemistry: A Foundation](https://www.bartleby.com/isbn_cover_images/9781337399425/9781337399425_largeCoverImage.gif)
Concept explainers
(a)
Interpretation:
Given chemical equation should be balanced.
Concept Introduction:
Balanced chemical equation gives the details about the identities of the reactants and products and also how much of each reactant and product participate in the reaction. The numbers in the balanced equation (coefficients) enable us to determine how much product we can get from a given quantity of reactants.
Normally the unbalanced equations are balanced by inspection starting with the most complicated molecule. We should determine what coefficient is necessary to equalize the number of each type of atoms on both side of the arrow. The coefficients used should be the smallest integers which balance the equation.
![Check Mark](/static/check-mark.png)
Answer to Problem 17CR
Explanation of Solution
The given reaction is as follows:
In this unbalanced equation number of Na atoms in reactants side is two and only one in the product side. Give coefficient 2 to NaCl. Then number of Cl atoms in products side becomes two, and there are two atoms in reactants side also. Other atoms present in the equation are already balanced. So, the balanced equation will be as follows:
(b)
Interpretation:
Given chemical equation should be balanced.
Concept Introduction:
Balanced chemical equation gives the details about the identities of the reactants and products and also how much of each reactant and product participate in the reaction. The numbers in the balanced equation (coefficients) enable us to determine how much product we can get from a given quantity of reactants.
Normally the unbalanced equations are balanced by inspection starting with the most complicated molecule. We should determine what coefficient is necessary to equalize the number of each type of atoms on both side of the arrow. The coefficients used should be the smallest integers which balance the equation.
![Check Mark](/static/check-mark.png)
Answer to Problem 17CR
Explanation of Solution
The equation is already balanced. Number of Zn atoms, H atoms and O atoms are same on both sides of the reaction arrow that is reactant and product sides.
(c)
Interpretation:
Given chemical equation should be balanced.
Concept Introduction:
Balanced chemical equation gives the details about the identities of the reactants and products and also how much of each reactant and product participate in the reaction. The numbers in the balanced equation (coefficients) enable us to determine how much product we can get from a given quantity of reactants.
Normally the unbalanced equations are balanced by inspection starting with the most complicated molecule. We should determine what coefficient is necessary to equalize the number of each type of atoms on both side of the arrow. The coefficients used should be the smallest integers which balance the equation.
![Check Mark](/static/check-mark.png)
Answer to Problem 17CR
Explanation of Solution
In the unbalanced equation, number of Na atoms in reactants side is one and in products side its three. So, give coefficient 3 to NaOH. The number of H atoms in the reactants side becomes six. Give coefficient 3 to H2 O to balance the number of H atoms. Thus, the balanced
(d)
Interpretation:
Given chemical equation should be balanced.
Concept Introduction:
Balanced chemical equation gives the details about the identities of the reactants and products and also how much of each reactant and product participate in the reaction. The numbers in the balanced equation (coefficients) enable us to determine how much product we can get from a given quantity of reactants.
Normally the unbalanced equations are balanced by inspection starting with the most complicated molecule. We should determine what coefficient is necessary to equalize the number of each type of atoms on both side of the arrow. The coefficients used should be the smallest integers which balance the equation.
![Check Mark](/static/check-mark.png)
Answer to Problem 17CR
Explanation of Solution
In the unbalanced equation, number of aluminum in reactants side is one but two in products side thus, give coefficient 2 to Al. Now, number of Mn in reactants side is two, but one in products side. Give coefficient 2 to Mn to balance the number of Mn atoms. The number of O is already balanced. Thus, the balanced equation is,
(e)
Interpretation:
Given chemical equation should be balanced.
Concept Introduction:
Balanced chemical equation gives the details about the identities of the reactants and products and also how much of each reactant and product participate in the reaction. The numbers in the balanced equation (coefficients) enable us to determine how much product we can get from a given quantity of reactants.
Normally the unbalanced equations are balanced by inspection starting with the most complicated molecule. We should determine what coefficient is necessary to equalize the number of each type of atoms on both side of the arrow. The coefficients used should be the smallest integers which balance the equation.
![Check Mark](/static/check-mark.png)
Answer to Problem 17CR
Explanation of Solution
In the unbalanced equation, number of C in reactants side is seven but one in products side. Give coefficient 7 to CO2. Number of H atoms in reactants side is six, but only two in the products side thus, give coefficient 3 to H2 O. The number of O atoms in the products side becomes 17, but there are only four in the reactants side thus, give coefficient 15/2 to before O2. But one cannot keep fractions as a coefficient in a balanced equation thus, multiply the whole equation by two so that the denominator of 15/2 is cancelled off. Thus, the balanced equation will be:
(f)
Interpretation:
Given chemical equation should be balanced.
Concept Introduction:
Balanced chemical equation gives the details about the identities of the reactants and products and also how much of each reactant and product participate in the reaction. The numbers in the balanced equation (coefficients) enable us to determine how much product we can get from a given quantity of reactants.
Normally the unbalanced equations are balanced by inspection starting with the most complicated molecule. We should determine what coefficient is necessary to equalize the number of each type of atoms on both side of the arrow. The coefficients used should be the smallest integers which balance the equation.
![Check Mark](/static/check-mark.png)
Answer to Problem 17CR
Explanation of Solution
In the unbalanced equation, number of C in reactants side is six but one in products side. Give coefficient 6 to CO2. Number of H atoms in reactants side is 14, but only 2 atoms in the products side. Thus, give coefficient 7 to H2 O, the number of O in the products side becomes 19, but there are only two in the reactants side. Give coefficient 19/2 to O2. But one cannot keep fractions as a coefficient in a balanced equation. Therefore, multiply the whole equation by 2 so that the denominator of 19/2 is cancelled off. So, the balanced equation is,
(g)
Interpretation:
Given chemical equation should be balanced.
Concept Introduction:
Balanced chemical equation gives the details about the identities of the reactants and products and also how much of each reactant and product participate in the reaction. The numbers in the balanced equation (coefficients) enable us to determine how much product we can get from a given quantity of reactants.
Normally the unbalanced equations are balanced by inspection starting with the most complicated molecule. We should determine what coefficient is necessary to equalize the number of each type of atoms on both side of the arrow. The coefficients used should be the smallest integers which balance the equation.
![Check Mark](/static/check-mark.png)
Answer to Problem 17CR
Explanation of Solution
In the unbalanced equation, number of C in reactants side is three but one in products side. Give coefficient 3 to CO2. Number of H atoms in reactants side is fourteen, but only two in the products side. Thus, give coefficient 4 to H2 O. But then the number of O atoms in the products side becomes 10, but there are only 3 atoms in the reactants side. Thus, give coefficient 9/2 to O2. But one cannot keep fractions as a coefficient in a balanced equation. Therefore, one multiply the whole equation by 2 so that the denominator of 9/2 is cancelled off. Thus, the balanced equation is,
(h)
Interpretation:
Given chemical equation should be balanced.
Concept Introduction:
Balanced chemical equation gives the details about the identities of the reactants and products and also how much of each reactant and product participate in the reaction. The numbers in the balanced equation (coefficients) enable us to determine how much product we can get from a given quantity of reactants.
Normally the unbalanced equations are balanced by inspection starting with the most complicated molecule. We should determine what coefficient is necessary to equalize the number of each type of atoms on both side of the arrow. The coefficients used should be the smallest integers which balance the equation.
![Check Mark](/static/check-mark.png)
Answer to Problem 17CR
Explanation of Solution
In the unbalanced equation, number of H atoms in the reactants side is 1 but in the products side, it is 2. Thus, give coefficient 2 to HClO4. Then all the other atoms get balanced. Mg is already balanced. Thus, the balanced equation will be:
Want to see more full solutions like this?
Chapter 7 Solutions
Introductory Chemistry: A Foundation
- Please answer the question and provide a detailed drawing of the structure. If there will not be a new C – C bond, then the box under the drawing area will be checked. Will the following reaction make a molecule with a new C – C bond as its major product: Draw the major organic product or products, if the reaction will work. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry.arrow_forwardPlease do not use AI. AI cannot "see" the molecules properly, and it therefore gives the wrong answer while giving incorrect descriptions of the visual images we're looking at. All of these compounds would be produced (I think). In my book, I don't see any rules about yield in this case, like explaining that one product would be present in less yield for this reason or that reason. Please explain why some of these produce less yield than others.arrow_forwardPlease answer the question and provide detailed explanations.arrow_forward
- All of these compounds would be produced (I think). In my book, I don't see any rules about yield in this case, like explaining that one product would be present in less yield for this reason or that reason. Please explain why some of these produce less yield than others.arrow_forward5. Fill in the missing molecules in the following reaction pathway. TMSO Heat + CI then HF O₂N (1.0 equiv) AICI 3 OMearrow_forwarde. O₂N NO2 1. excess H2, Pd/C 2. excess NaNO2, HCI 3. excess CuCNarrow_forward
- Help with a periodic table task.' Procedure Part 1: Customizing a Periodic Table Use a textbook or other valid source to determine which elements are metals, nonmetals, metalloids (called semimetals in some texts), alkali metals, alkaline earth metals, transition metals, halogens, and noble gases. Download and print a copy of the Periodic Table of Elements. Use colored pencils, colorful highlighters, or computer drawing tools to devise a schematic for designating each of the following on the periodic table: Group numbers Period number Labels for these groups: alkali metals, alkaline earth metals, transition metals, inner transition metals (lanthanides and actinides), other metals, metalloids (semimetals), other nonmetals, halogens, and noble gases Metals, nonmetals, and metalloids Note: Write the group and period numbers and color/highlight each element for categorization. Be sure to include a key for the schematic. Take a photo of the completed periodic table and upload the…arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardCan you explain these two problems for mearrow_forward
- 个 ^ Blackboard x Organic Chemistry II Lecture (m x Aktiv Learning App x → C app.aktiv.com ← Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Problem 28 of 35 :OH H HH KO Select to Edit Arrows CH CH₂OK, CH CH2OH 5+ H :0: Donearrow_forwardCan you explain those two problems for me please.arrow_forwardDo we need to draw the "ethyne" first for this problem? im confusedarrow_forward
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- Introductory Chemistry: A FoundationChemistryISBN:9781285199030Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305580343/9781305580343_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337398909/9781337398909_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285199047/9781285199047_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285199030/9781285199030_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079243/9781305079243_smallCoverImage.gif)