Vector Mechanics for Engineers: Statics
Vector Mechanics for Engineers: Statics
12th Edition
ISBN: 9781259977268
Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek
Publisher: McGraw-Hill Education
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Chapter 6.3, Problem 6.121P

6.119 through 6.121 Each of the frames shown consists of two L-shaped members connected by two rigid links. For each frame, determine the reactions at the supports and indicate whether the frame is rigid.

Chapter 6.3, Problem 6.121P, 6.119 through 6.121 Each of the frames shown consists of two L-shaped members connected by two rigid

Fig. P6.121

Expert Solution & Answer
Check Mark
To determine

The reactions at the frame and the rigidness of the frame.

Answer to Problem 6.121P

The reactions at the frame for figure (a) is B=2P_ towards right, A=2.24P_ at 26.6°_ above the positive x axis and the rigidness of the frame in figure (a) rigid, for figure (b) the reaction is P=0 and the system is not rigid, and for figure (c) the reactions are A=P_ upwards, C=P_ upwards, B=P_ and the system is rigid.

Explanation of Solution

The following figure gives the free body diagram of the first part of the member in figure P6.121(a).

Vector Mechanics for Engineers: Statics, Chapter 6.3, Problem 6.121P , additional homework tip  1

Write the equation to find the moment of force.

M=Fa

Here, F is the force acting and a is the perpendicular distance from the force to the point about which the moment is calculated.

Write the equation to find the total moment about the point A.

ΣMA=Σ(Fa)

Write the equations for equilibrium for the free body diagram in figure 1.

ΣMA=0 (I)

ΣFx=0 (II)

ΣFy=0 (III)

Here, MA is the torque about the point A, Fy is the force in the y direction, and Fx is the force in the x direction.

The following figure gives the free body diagram of the second part of the member in figure P6.121(a).

Vector Mechanics for Engineers: Statics, Chapter 6.3, Problem 6.121P , additional homework tip  2

Write the equations for equilibrium for the free body diagram in figure 2.

ΣMB=0 (IV)

ΣFx=0 (V)

ΣFy=0 (VI)

Here, Fx is the force in the x direction, Fy is the force in the y direction and MB is the torque about the point B.

The following figure gives the free body diagram of the first part of the member in figure P6.119(b).

Vector Mechanics for Engineers: Statics, Chapter 6.3, Problem 6.121P , additional homework tip  3

Write the equations for equilibrium for the free body diagram in figure 3.

ΣME=0 (VII)

Here, ME is the torque about the point E.

The following figure gives the free body diagram of the second part of the member in figure P6.119(b).

Vector Mechanics for Engineers: Statics, Chapter 6.3, Problem 6.121P , additional homework tip  4

Write the equations for equilibrium for the free body diagram in figure 4.

ΣMB=0 (VIII)

Here, MB is the torque about the point B.

The following figure gives the free body diagram of the member in figure P6.119(c).

Vector Mechanics for Engineers: Statics, Chapter 6.3, Problem 6.121P , additional homework tip  5

Write the equations for equilibrium for the free body diagram in figure 5.

ΣFy=0 (IX)

ΣMD=0 (X)

ΣFx=0 (XI)

Here, MD is the torque about the point D, Fx is the force in the x direction, and Fy is the force in the y direction.

The following figure gives the free body diagram of right part of the member in figure P6.119(c).

Vector Mechanics for Engineers: Statics, Chapter 6.3, Problem 6.121P , additional homework tip  6

Write the equations for equilibrium for the free body diagram in figure 6.

ΣMD=0 (XII)

ΣFx=0 (XIII)

Here, MD is the torque about the point D, and Fx is the force in the x direction.

Write the expression to find the magnitude of the vector from its components.

C=Cx2+Cy2 (XIV)

Here,Cx is the x component of the vector C and Cy is the y component of the vector C.

Write the equation to find the angle of orientation of the vector C.

θ=tan1(CyCx) (XV)

Conclusion:

Solve equation (I) using figure 1.

aF12aP=0

Rewrite the above equation.

F1=2P

Solve equation (III) using figure 1.

AyP=0

Rewrite the above equation.

Ay=P

Solve equation (IV) using figure 2.

aF2=0

Rewrite the above equation.

F2=0

Solve equation (V) using figure 2.

Bx+F1=0

Substitute 2P for F1 and rewrite the above equation to find Bx.

Bx=F1=2P

Solve equation (VI) using figure 2.

AxF1+F2=0

Substitute 2P for F1, 0 for F2 and rewrite the above equation to find Ax.

Ax=F1+F2=2P+0=2P

Rewrite equation (XIV) in terms of the vector A.

A=Ax2+Ay2

Substitute 2P for Ax, and P for Ay in the above equation.

A=(2P)2+(P)2=2.236P

Rewrite equation (XV) in terms of the vector A.

θ=tan1(AyAx)

Substitute 2P for Ax, and P for Ay in the above equation.

θ=tan1(P2P)=26.56°

Rewrite equation (XIV) in terms of the vector B.

B=Bx2+By2

Substitute 2P for Bx, and 0 for By in the above equation.

B=(2P)2+(0)2=2P

Solve equation (VII) using figure 3.

a2P+a2Ax5a2Ay=0

Rewrite the above equation.

Ax5Ay=P

Solve equation (VIII) using figure 4.

3aP+aAx5aAy=0

Rewrite the above equation.

Ax5Ay=3P

Solve the conditions obtained from figure 3 and 4.

P=0

Solve equation (IX) using figure 5.

AP=0

Rewrite the above equation to find A.

A=P

Solve equation (X) using figure 5.

aF12aA=0

Substitute P for A and rewrite the above equation to find F1.

F1=2P

Solve equation (XI) using figure 5.

F2F1=0

Substitute 2P for F1 and rewrite the above equation to find F2.

F2=F1=2P

Solve equation (XII) using figure 6.

2aCaF1=0

Substitute 2P for F1 and rewrite the above equation to find C.

C=F12=P

Solve equation (XII) to the right using figure 6.

F1F2+Bx=0

Substitute 2P for F1, 2P for F2 and rewrite the above equation to find Bx.

Bx=F1+F2=2P+2P=0

Solve equation (XII) upwards using figure 6.

Bx+C=0

Substitute P for C and rewrite the above equation to find Bx.

Bx=C=P

Therefore, the reactions at the frame for figure (a) is B=2P_ towards right, A=2.24P_ at 26.6°_ above the positive x axis and the rigidness of the frame in figure (a) rigid, for figure (b) the reaction is P=0 and the system is not rigid, and for figure (c) the reactions are A=P_ upwards, C=P_ upwards, B=P_ and the system is rigid.

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Chapter 6 Solutions

Vector Mechanics for Engineers: Statics

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