Explanation The free body diagram of upper handle is shown below The symmetry of figure 1 gives the relation between F C D x and F C D y F C D x 2 in . = F C D y 2.4 in . F C D y = 1.2 in . × F C D x (I) Here, F C D x and F C D y are the components of force as shown in figure 1, Write the expression for moment at A using figure 1 ∑ M A = F × d ⊥ (II) Here, F is the force, d ⊥ is the perpendicular distance between A and point where force is acting, and M A is the moment at A At equilibrium the moment at A will be zero ∑ M A = F × d ⊥ = 0 (III) Write the complete expression for the total moment at A using figure 1 under equilibrium is ∑ M A = F C D y ( 4 in . ) − ( 1.5 in . ) F C D x − ( 13.2 in . ) 90 lb = 0 (IV) By the symmetry of figure the force F D E will be equal to F E

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Chapter 6.4, Problem 6.146P

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The magnitude of force exerted on the piston at D when two 90 lb forces are applied.

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Chapter 6.4, Problem 6.145P

Chapter 6.4, Problem 6.147P

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The magnitude of force exerted on the piston at D when two 90 lb forces are applied.

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