Chapter 6.2, Problem 28PPE

To determine

To find: If the given system of equations has one, infinitely many or no solution.

Answer to Problem 28PPE

No solution

Explanation of Solution

Given information:

The equations $x=-7y+34$ and $x+7y=32$

Calculation:

Substitute $-7y+34$ for x in equation $x+7y=32$

  $\left(-7y+34\right)+7y=32$

Now simplify above equation.

  $\begin{array}{l}\left(-7y+34\right)+7y=32\\ \Rightarrow -7y+7y+34=32\\ \Rightarrow 34=32\end{array}$

Since $34\ne 32$ , therefore the given system of equations have no solution.