Chapter 6.1, Problem 15PPE

To determine

To solve: given system of linear equation by graphing.

Answer to Problem 15PPE

  $x=-3\text{ and }y=-11$

Explanation of Solution

Given information: a system of linear equation is given as follows-

  $\begin{array}{l}4x-y=-1\\ -x+y=x-5\end{array}$

$4x-y=-1$
$x$	-3	0
$y$	-11	1

$-x+y=x-5$
$x$	-3	0
$y$	-11	-5

Taking two points from the table we can draw the graphs, and the intersecting point is solution of given system of linear equation.

Graph:

  

Check:

Putting (-3, -11) in equation, $4x-y=-1$ we get,

  $\begin{array}{l}4(-3)-(-11)=-1\\ -12+11=-1\\ -1=-1\end{array}$

Again putting (-3, -11) in equation $-x+y=x-5$ , we get,

  $\begin{array}{l}-(-3)+(-11)=-3-5\\ 3-11=-8\\ -8=-8\end{array}$

Hence the point (-3, -11) satisfies both the equation.