Chapter 6, Problem 84E

Interpretation Introduction

Interpretation:

Among the following visualization, the best one should be determined which represents the distribution of ${\text{SO}}_{\text{2}}$ and ${\text{O}}_{\text{2}}$ gas molecules near an orifice and after some time effusion takes place in the direction denoted by arrows.

Concept introduction:

The effusion of gases through orifice can be explained with the help of Graham’s law of effusion. According to the Graham’s law of effusion, rate of effusion of any gas is always inversely proportional to the square root of the mass of gaseous particles.

The mathematical expression for this law is:

$\frac{\text{Rate of effusion of gas 1}}{\text{Rate of effusion of gas 2}}\text{=}\sqrt{\frac{{\text{M}}_{\text{2}}}{{\text{M}}_{\text{1}}}}$

Here, M₁ and M₂ represent the molar mass of gases.

In terms of time for gases;

$\frac{\text{Effusion time of gas 1}}{\text{Effusion time of gas 2}}\text{=}\sqrt{\frac{{\text{M}}_{\text{1}}}{{\text{M}}_{\text{2}}}}$