Chapter 6, Problem 111IAE

Interpretation Introduction

(a)

Interpretation:

Percent of water vapor by volume should be calculated.

Concept introduction:

In the mixture of gases, the volume percent of gas A can be calculated as follows:

$\text{Volume percent of gas A =}\frac{{\text{V}}_{\text{A}}}{{\text{V}}_{\text{Total}}}\text{×1}00\%$

Here,

$\frac{{\text{n}}_{\text{A}}}{{\text{n}}_{\text{total}}}\text{ = }\frac{{\text{P}}_{\text{A}}}{{\text{P}}_{\text{total}}}\text{ = }\frac{{\text{V}}_{\text{A}}}{{\text{V}}_{\text{total}}}{\text{ = x}}_{\text{A}}$

And,

${\text{x}}_{\text{A}}$ is mole fraction of gas A.

Interpretation Introduction

(b)

Interpretation:

The percent of water vapor by number of molecules should be calculated.

Concept introduction:

The molecule percent of gas A in the mixture can be calculated as follows:

$\begin{array}{l}\text{Molecule percent of gas A =}\frac{{\text{Molecule}}_{\text{A}}}{\text{Total molecules}}\text{×1}00\%\\ \frac{{\text{n}}_{\text{A}}}{{\text{n}}_{\text{total}}}\text{ = }\frac{{\text{P}}_{\text{A}}}{{\text{P}}_{\text{total}}}\text{ = }\frac{{\text{V}}_{\text{A}}}{{\text{V}}_{\text{total}}}{\text{ = x}}_{\text{A}}\end{array}$

Interpretation Introduction

(c)

Interpretation:

Percent of water vapor by mass should be calculated.

Concept introduction:

Ideal gas equation for the gases;

$\text{PV = nRT}$

P − Pressure

V − Volume of the container

N - Number of moles

R − Universal gas constant

T − Absolute temperature

Mass = number of moles x molecular mass

$\text{Mass percent of gas A =}\frac{{\text{Mass}}_{\text{A}}}{\text{Total mass}}\text{×100\%}$