Chapter 6, Problem 6M.3AST

Interpretation Introduction

Interpretation:

The net standard potential of $\left({\text{Au}}^{\text{3+}}{\text{/Au}}^{\text{+}}\right)$ has to be calculated.

Concept Introduction:

The Gibbs free energy of the reaction is calculated as,

  ${\text{ΔG=-nFE}}_{\text{cell}}$

Here, $\text{ΔG=}$ Gibbs free energy

    $\text{n=}$ Number of electrons transferred (in moles)

  $\text{F=}$ Faraday’s constant $\left(\text{9}{\text{.6485×10}}^{\text{4}}\text{C}\cdot {\text{mol}}^{\text{-1}}\right)$

  ${\text{E}}_{\text{cell}}\text{=}$ Cell potential