Explanation The unbalanced skeletal equation for the reaction is, MnO 4 − (aq) +H 2 SO 3 (aq) → HSO 4 − (aq) +Mn 2+ (aq) The balanced net ionic equation is explained detail in systematic manner, which is shown below. Reduction half reaction: The oxidation number of Mn is decreased from + 7 to + 2 , therefore this is reduction reaction. MnO 4 - (aq) → Mn 2+ (aq) Balance the O atom by adding H 2 O right side MnO 4 - (aq) → Mn 2+ (aq) +4H 2 O (l) Balance the H atom by adding H + ion on the left side MnO 4 - (aq) +8H + → Mn 2+ (aq) +4H 2 O (l) Balancing the net charges by adding electrons. Here, in left side, the net charge is + 7 and the right side the net charge is + 2 , therefore it required 5 electrons on the left side to reduce the charge from + 7 to + 2 . MnO 4 - (aq) +8H + +5e - → Mn 2+ (aq) +4H 2 O (l) Oxidation half reaction: The oxidation number of S is increased from + 4 to + 6 , therefore this is oxidation reaction. H 2 SO 3 (aq) → HSO 4 − (aq) Balance the O atom by adding H 2 O left side H 2 SO 3 (aq) +H 2 O (l) → HSO 4 − (aq) Balance the H atom by adding H + ion on the right side H 2 SO 3 (aq) +H 2 O (l) → HSO 4 − (aq) +3H + Balance the net charges by adding the electrons

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM

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ISBN: 9781319399849

Author: ATKINS

Publisher: MAC HIGHER

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Chapter 6, Problem 6K.1BST

Interpretation Introduction

Interpretation:

The balanced net ionic equation for the reaction of acidified potassium permanganate solution react with sulfurous acid to form sulfuric acid and manganese(II) ions has to be derived.

Concept Introduction:

Net ionic equation:

Net ionic equation is defined as the specific species that only involves to a particular reaction. This type of equations is generally used in acid-base neutralization reactions and redox reactions.

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Chapter 6, Problem 6K.1AST

Chapter 6, Problem 6K.2AST

Chapter 6 Solutions

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM

Ch. 6 - Prob. 6A.1AST Ch. 6 - Prob. 6A.1BST Ch. 6 - Prob. 6A.2AST Ch. 6 - Prob. 6A.2BST Ch. 6 - Prob. 6A.3AST Ch. 6 - Prob. 6A.3BST Ch. 6 - Prob. 6A.1E Ch. 6 - Prob. 6A.2E Ch. 6 - Prob. 6A.3E Ch. 6 - Prob. 6A.4E

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Solution Summary: The author explains the balanced net ionic equation for acidified potassium permanganate solution react with sulfurous acid to form sulfuric acid and manganese(II) ions.

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Chapter 6 Solutions