Explanation Given that, the buffer contains 0.040 M N a C H 3 C O 2 ( a q ) and 0.080 M C H 3 C O O H ( a q ) . The addition of a strong acid will react with the conjugate base and thus decreases the concentration of conjugate base and increases the concentration of weak acid. The proton transfer equilibrium is given below. C H 3 C O O H ( a q ) + H 2 O ( l ) ⇌ H 3 O + ( a q ) + C H 3 C O 2 − ( a q ) K a = [ H 3 O + ] [ C H 3 C O 2 − ] [ C H 3 C O O H ] = 1.8 × 10 − 5 The reaction of added acid with some of C H 3 C O O − is given below. C H 3 C O O − ( a q ) + H + ( a q ) → C H 3 C O 2 H ( a q ) The initial number of moles of acid can be calculated as shown below. n ( C H 3 C O O H ) i n i t i a l = 0.500 L × 0.080 m o l . L − 1 = 0.04 m o l The new concentration of weak acid can be calculated as shown below. n ( C H 3 C O O H ) f i n a l = 0.04 m o l + 0.010 m o l = 0.05 m o l [ C H 3 C O O H ] = M o l e s V o l u m e = 0.05 m o l 0.500 L = 0.01 M The molar ratio of conjugate base and added acid is 1 : 1. The number of reacted moles of conjugate base after addition of 0.0100 m o l o f H C l can be calculated as given below. n ( C H 3 C O O − ) r e a c t s = 0.0100 m o l H + × 1 m o l C H 3 C O O − 1 m o l H + = 0

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM

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ISBN: 9781319399849

Author: ATKINS

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Chapter 6, Problem 6G.2BST

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The pH of the resulting solution and the change in pH has to be calculated.

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Chapter 6, Problem 6G.2AST

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Chapter 6 Solutions

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM

Ch. 6 - Prob. 6A.1AST Ch. 6 - Prob. 6A.1BST Ch. 6 - Prob. 6A.2AST Ch. 6 - Prob. 6A.2BST Ch. 6 - Prob. 6A.3AST Ch. 6 - Prob. 6A.3BST Ch. 6 - Prob. 6A.1E Ch. 6 - Prob. 6A.2E Ch. 6 - Prob. 6A.3E Ch. 6 - Prob. 6A.4E

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The p H of the resulting solution and the change in p H has to be calculated.

Solution Summary: The author explains that the pH of the resulting solution and the change in pH has to be calculated.

Interpretation:

The pH of the resulting solution and the change in pH has to be calculated.

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Chapter 6 Solutions

The p H of the resulting solution and the change in p H has to be calculated.

Solution Summary: The author explains that the pH of the resulting solution and the change in pH has to be calculated.

Interpretation: The pH of the resulting solution and the change in pH has to be calculated.

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Chapter 6 Solutions

Interpretation:

The pH of the resulting solution and the change in pH has to be calculated.