Chapter 6, Problem 6.77P

Interpretation Introduction

(a)

Interpretation:

The given reaction is:

  $\text{CO}+{\text{H}}_{\text{2}}\text{O}\underset{}{\overset{}{\rightleftarrows }}{\text{CO}}_{\text{2}}+{\text{H}}_{\text{2}}$

The expression for the equilibrium constant is to be written.

Concept Introduction:

The equilibrium constant is denoted by K.

When both the reactants and products have the same value, then the reaction is in equilibrium.

Interpretation Introduction

(b)

Interpretation:

The given reaction is

  $\mathrm{CO}+H_{2}O\underset{}{\overset{}{\rightleftarrows }}C{O}_2+H_2$

The equilibrium constant is to be calculated for the given concentration for each substance:

  $\begin{array}{l}\text{CO=0}\text{.090M}\\ {\text{H}}_{\text{2}}\text{O=0}\text{.12M}\\ {\text{CO}}_{\text{2}}\text{=0}\text{.15M}\\ {\text{H}}_{\text{2}}\text{=0}\text{.30M}\end{array}$

Concept Introduction:

The equilibrium constant is denoted by K.

Its formula is:

  $K=\frac{\mathrm{Products}}{\mathrm{Reactants}}$