Essentials Of Materials Science And Engineering
4th Edition
ISBN: 9781337670845
Author: ASKELAND
Publisher: Cengage
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Question
Chapter 6, Problem 6.27P
Interpretation Introduction
(a)
Interpretation:
The cross-sectional area of the hoist of a cable is 80mm2. Crate of 500 kg is lifted by this hoist and the length of cable is 30 m. It is assumed that the deformation is elastic. The stress of cable is to be determined.
Concept Introduction:
Following formulas will be used for the calculation of stress of cable.
And
Interpretation Introduction
(b)
Interpretation:
The cross-sectional area of the hoist of a cable is 80mm2. Crate of 500 kg is lifted by this hoist and the length of cable is 30 m. It is assumed that the deformation is elastic. Elongation of cable is to be determined considering that it is made from steel. And modulus of elasticity (E) is 200GPa.
Concept Introduction:
Concept of Hooke's law will be used. Hooke's law gives the following relation-
Interpretation Introduction
(c)
Interpretation:
The cross-sectional area of the hoist of a cable is 80mm2. Crate of 500 kg is lifted by this hoist and the length of cable is 30 m. It is assumed that the deformation is elastic. Elongation of cable is to be determined considering that it is made from polypropylene. And modulus of elasticity (E) is 1.2GPa.
Concept Introduction:
Concept of Hooke's law will be used. Hooke's law gives the following relation-
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Q3.
a) Given the unsymmetrical phasors for a three-phase system, they can be
represented in terms of their symmetrical components as follows:
[Fa]
[1 1
Fb = 1 a²
[Fc.
11[Fao]
a Fai
1 a a2F a2-
where F stands for any three-phase quantity. Conversely, the sequence
components can be derived from the unsymmetrical phasors as:
[11 1] [Fal
Faol
Fa1 =
1 a a² F
1 a²
a
a2.
Given the unbalanced three-phase voltages:
V₁ = 120/10° V, V₂ = 200/110° V, V = 240/200° V
Calculate in polar form the sequence components of the voltage.
Complete the table of values for this circuit:
*P2.58. Solve for the node voltages shown in Figure
P2.58.
-
10 Ω
w
+
10 Ω
15 Ω
w
w
'+'
5 Ω
20x
1 A
Figure P2.58
w
V2
502 12A
Chapter 6 Solutions
Essentials Of Materials Science And Engineering
Ch. 6 - Prob. 6.1PCh. 6 - Prob. 6.2PCh. 6 - Prob. 6.3PCh. 6 - Prob. 6.4PCh. 6 - Prob. 6.5PCh. 6 - Prob. 6.6PCh. 6 - Prob. 6.7PCh. 6 - Prob. 6.8PCh. 6 - Prob. 6.9PCh. 6 - Prob. 6.10P
Ch. 6 - Prob. 6.11PCh. 6 - Prob. 6.12PCh. 6 - Prob. 6.13PCh. 6 - Prob. 6.14PCh. 6 - Prob. 6.15PCh. 6 - Prob. 6.16PCh. 6 - Prob. 6.17PCh. 6 - Prob. 6.18PCh. 6 - Prob. 6.19PCh. 6 - Prob. 6.20PCh. 6 - Prob. 6.21PCh. 6 - Prob. 6.22PCh. 6 - Prob. 6.23PCh. 6 - Prob. 6.24PCh. 6 - Prob. 6.25PCh. 6 - Prob. 6.26PCh. 6 - Prob. 6.27PCh. 6 - Prob. 6.28PCh. 6 - Prob. 6.29PCh. 6 - Prob. 6.30PCh. 6 - Prob. 6.31PCh. 6 - Prob. 6.32PCh. 6 - Prob. 6.33PCh. 6 - Prob. 6.34PCh. 6 - Prob. 6.35PCh. 6 - Prob. 6.36PCh. 6 - Prob. 6.37PCh. 6 - Prob. 6.38PCh. 6 - Prob. 6.39PCh. 6 - Prob. 6.40PCh. 6 - Prob. 6.41PCh. 6 - Prob. 6.42PCh. 6 - Prob. 6.43PCh. 6 - Prob. 6.44PCh. 6 - Prob. 6.45PCh. 6 - Prob. 6.46PCh. 6 - Prob. 6.47PCh. 6 - Prob. 6.48PCh. 6 - Prob. 6.49PCh. 6 - Prob. 6.50PCh. 6 - Prob. 6.51PCh. 6 - Prob. 6.52PCh. 6 - Prob. 6.53PCh. 6 - Prob. 6.54PCh. 6 - Prob. 6.55PCh. 6 - Prob. 6.56PCh. 6 - Prob. 6.57PCh. 6 - Prob. 6.58PCh. 6 - Prob. 6.59PCh. 6 - Prob. 6.60PCh. 6 - Prob. 6.61PCh. 6 - Prob. 6.62PCh. 6 - Prob. 6.63PCh. 6 - Prob. 6.64PCh. 6 - Prob. 6.65PCh. 6 - Prob. 6.66PCh. 6 - Prob. 6.67PCh. 6 - Prob. 6.68PCh. 6 - Prob. 6.69PCh. 6 - Prob. 6.70PCh. 6 - Prob. 6.71PCh. 6 - Prob. 6.72PCh. 6 - Prob. 6.73PCh. 6 - Prob. 6.74PCh. 6 - Prob. 6.75PCh. 6 - Prob. 6.77PCh. 6 - Prob. 6.78PCh. 6 - Prob. 6.79PCh. 6 - Prob. 6.80PCh. 6 - Prob. 6.81PCh. 6 - Prob. 6.82PCh. 6 - Prob. K6.1KP
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