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Chapter 6, Problem 6.13P
Interpretation Introduction

(a)

Interpretation: Whether the starting material or product is favored at equilibrium is to be predicted on the basis of the given value of ΔH°.

Concept introduction: The change in Gibbs free energy and enthalpy is represented by ΔG° and ΔH° respectively. They both are state functions. The relation of ΔG° and ΔH° is shown as,

ΔG°=ΔH°TΔS°

The change in Gibbs free energy describes the spontaneity of the reaction, whereas the change in enthalpy describes the relative bond strength in the substance.

Interpretation Introduction

(b)

Interpretation: The starting material or product which is favored at equilibrium is to be identified.

Concept introduction: The change in Gibbs free energy and enthalpy is represented by ΔG° and ΔH° respectively. They both are state functions. The relation of ΔG° and ΔH° is shown as,

ΔG°=ΔH°TΔS°

The change in Gibbs free energy describes the spontaneity of the reaction, whereas the change in enthalpy describes the relative bond strength in the substance.

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Given each value, determine whether the starting material or product is favored at equilibrium. a.Keq = 0.5 b.ΔGo = −100 kJ/mol c.ΔHo = 8.0 kJ/mol d.Keq = 16 e. ΔGo = 2.0 kJ/mol f.ΔHo = 200 kJ/mol g. ΔSo = 8 J/(K•mol) h.ΔSo = −8 J/(K•mol)
Considering each of the following values and neglecting entropy, tell whether the starting material or product is favored at equilibrium: (a) ΔHo = 80 kJ/mol; (b) ΔHo = −40 kJ/mol.
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Chapter 6 Solutions

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card

Ch. 6 - Given each of the following values, is the...Ch. 6 - The equilibrium constant for the conversion of the...Ch. 6 - Prob. 6.13PCh. 6 - For a reaction with H=40kJ/mol, decide which of...Ch. 6 - For a reaction with H=20kJ/mol, decide which of...Ch. 6 - Draw an energy diagram for a reaction in which the...Ch. 6 - Prob. 6.17PCh. 6 - Prob. 6.18PCh. 6 - Problem 6.19 Consider the following energy...Ch. 6 - Draw an energy diagram for a two-step reaction,...Ch. 6 - Which value if any corresponds to a faster...Ch. 6 - Prob. 6.22PCh. 6 - Problem 6.23 For each rate equation, what effect...Ch. 6 - Prob. 6.24PCh. 6 - Identify the catalyst in each equation. a....Ch. 6 - Draw the products of homolysis or heterolysis of...Ch. 6 - Explain why the bond dissociation energy for bond...Ch. 6 - Classify each transformation as substitution,...Ch. 6 - Prob. 6.29PCh. 6 - 6.30 Draw the products of each reaction by...Ch. 6 - 6.31 (a) Add curved arrows for each step to show...Ch. 6 - Prob. 6.32PCh. 6 - Prob. 6.33PCh. 6 - Prob. 6.34PCh. 6 - Calculate H for each reaction. a HO+CH4CH3+H2O b...Ch. 6 - Homolysis of the indicated CH bond in propene...Ch. 6 - Prob. 6.37PCh. 6 - Prob. 6.38PCh. 6 - 6.39. a. Which value corresponds to a negative...Ch. 6 - Prob. 6.40PCh. 6 - For which of the following reaction is S a...Ch. 6 - Prob. 6.42PCh. 6 - Prob. 6.43PCh. 6 - 6.44 Consider the following reaction: . Use curved...Ch. 6 - Prob. 6.45PCh. 6 - Draw an energy diagram for the Bronsted-Lowry...Ch. 6 - Prob. 6.47PCh. 6 - Indicate which factors affect the rate of a...Ch. 6 - Prob. 6.49PCh. 6 - 6.50 The conversion of acetyl chloride to methyl...Ch. 6 - Prob. 6.51PCh. 6 - Prob. 6.52PCh. 6 - The conversion of (CH3)3Cl to (CH3)2C=CH2 can...Ch. 6 - 6.54 Explain why is more acidic than , even...Ch. 6 - Prob. 6.55PCh. 6 - Prob. 6.56PCh. 6 - Prob. 6.57PCh. 6 - Although Keq of equation 1 in problem 6.57 does...Ch. 6 - Prob. 6.59P
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