University Physics with Modern Physics (14th Edition)
14th Edition
ISBN: 9780321973610
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Chapter 6, Problem 6.12E
A boxed 10.0-kg computer monitor is drugged by friction 5.50 m upward along a conveyor belt inclined at an angle of 36.9° above the horizontal. If the monitor’s speed is a constant 2.10 cm/s, how much work is done on the monitor by (a) friction, (b) gravity, and (c) the normal force of the conveyor belt?
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Chapter 6 Solutions
University Physics with Modern Physics (14th Edition)
Ch. 6.1 - An electron moves in a straight line toward the...Ch. 6.2 - Rank the following bodies in order of their...Ch. 6.3 - In Example 5.20 (Section 5.4) we examined a...Ch. 6.4 - The air surrounding an airplane in flight exerts a...Ch. 6 - The sign of many physical quantities depends on...Ch. 6 - An elevator is hoisted by its cables at constant...Ch. 6 - A rope tied to a body is pulled, causing the body...Ch. 6 - If it takes total work W to give an object a speed...Ch. 6 - If there is a net nonzero force on a moving...Ch. 6 - In Example 5.5 (Section 5.1), how does the work...
Ch. 6 - In the conical pendulum of Example 5.20 (Section...Ch. 6 - For the cases shown in Fig. Q6.8, the object is...Ch. 6 - A force F is in the x-direction and has a...Ch. 6 - Does a cars kinetic energy change more when the...Ch. 6 - A falling brick has a mass of 1.5 kg and is moving...Ch. 6 - Can the total work done on an object during a...Ch. 6 - A net force acts on an object and accelerates it...Ch. 6 - A truck speeding down the highway has a lot of...Ch. 6 - You are holding a briefcase by the handle, with...Ch. 6 - When a book slides along a tabletop. the force of...Ch. 6 - Time yourself while running up a flight of steps,...Ch. 6 - Fractured Physics. Many terms from physics are...Ch. 6 - An advertisement for a portable electrical...Ch. 6 - A car speeds up while the engine delivers constant...Ch. 6 - Consider a graph of instantaneous power versus...Ch. 6 - A nonzero net force acts on an object. Is it...Ch. 6 - When a certain force is applied to an ideal...Ch. 6 - If work W is required to stretch a spring a...Ch. 6 - You push your physics book 1.50 m along a...Ch. 6 - Using a cable with a tension of 1350 N, a tow...Ch. 6 - A factory worker pushes a 30.0-kg crate a distance...Ch. 6 - Suppose the worker in Exercise 6.3 pushes downward...Ch. 6 - A 75.0-kg painter climbs a ladder that is 2.75 m...Ch. 6 - Two tugboats pull a disabled supertanker. Each tug...Ch. 6 - Two blocks are connected by a very light string...Ch. 6 - A loaded grocery cart is rolling across a parking...Ch. 6 - A 0.800-kg ball is tied to the end of a string...Ch. 6 - A 12.0-kg package in a mail-sorting room slides...Ch. 6 - A 128.0-N carton is pulled up a frictionless...Ch. 6 - A boxed 10.0-kg computer monitor is drugged by...Ch. 6 - A large crate sits on the floor of a warehouse....Ch. 6 - You apply a constant force F=(68.0N)i+(36.0N)j to...Ch. 6 - You are holding a briefcase by the handle, with...Ch. 6 - When a book slides along a tabletop, the force of...Ch. 6 - Time yourself while running up a flight of steps,...Ch. 6 - Fractured Physics. Many terms from physics are...Ch. 6 - Meteor Crater. About 50,000 years ago, a meteor...Ch. 6 - A 4.80-kg watermelon is dropped from rest from the...Ch. 6 - Use the work-energy theorem to solve each of these...Ch. 6 - Use the work-energy theorem to solve each of these...Ch. 6 - You are a member of an Alpine Rescue Team. You...Ch. 6 - You throw a 3.00-N rock vertically into the air...Ch. 6 - A sled with mass 12.00 kg moves in a straight line...Ch. 6 - A mass m slides down a smooth inclined plane from...Ch. 6 - A 12-pack of Omni-Cola (mass 4.30 kg) is initially...Ch. 6 - A soccer ball with mass 0.420 kg is initially...Ch. 6 - A little red wagon with mass 7.00 kg moves in a...Ch. 6 - A block of ice with mass 2.00 kg slides 1.35 m...Ch. 6 - Stopping Distance. A car is traveling on a level...Ch. 6 - A 30.0-kg crate is initially moving with a...Ch. 6 - BIO Heart Repair. A surgeon is using material from...Ch. 6 - To stretch a spring 3.00 cm from its unstretched...Ch. 6 - Three identical 8.50-kg masses are hung by three...Ch. 6 - A child applies a force F parallel to the x-axis...Ch. 6 - Suppose the sled in Exercise 6.36 is initially at...Ch. 6 - A spring of force constant 300.0 N/m and...Ch. 6 - A 6.0-kg box moving at 3.0 m/s on a horizontal,...Ch. 6 - Leg Presses. As part of your daily workout, you...Ch. 6 - (a) In Example 6.7 (Section 6.3) it was calculated...Ch. 6 - A 4.00-kg block of ice is placed against a...Ch. 6 - A force F is applied to a 2.0-kg, radio-controlled...Ch. 6 - Suppose the 2.0-kg model car in Exercise 6.43 is...Ch. 6 - Prob. 6.45ECh. 6 - Half or a Spring. (a) Suppose you cut a massless...Ch. 6 - A small glider is placed against a compressed...Ch. 6 - An ingenious bricklayer builds a device for...Ch. 6 - CALC A force in the +x-direction with magnitude...Ch. 6 - A crate on a motorized cart starts from rest and...Ch. 6 - How many joules of energy does a 100-watt light...Ch. 6 - BIO Should You Walk or Run? It is 5.0 km from your...Ch. 6 - Magnetar. Oil December 27, 2004, astronomers...Ch. 6 - A 20.0-kg rock is sliding on a rough, horizontal...Ch. 6 - A tandem (two-person) bicycle team must overcome a...Ch. 6 - When its 75-kW (100-hp) engine is generating full...Ch. 6 - Working Like a Horse. Your job is to lift 30-kg...Ch. 6 - An elevator has mass 600 kg, not including...Ch. 6 - A ski tow operates on a 15.0 slope of length 300...Ch. 6 - You are applying a constant horizontal force F =...Ch. 6 - BIO While hovering, a typical flying insect...Ch. 6 - CALC A balky cow is leaving the barn as you try...Ch. 6 - A luggage handler pulls a 20.0-kg suitcase up a...Ch. 6 - Chin-ups. While doing a chin-up, a man lifts his...Ch. 6 - Consider the blocks in Exercise 6.7 as they move...Ch. 6 - A 5.00-kg package slides 2.80 m down a long ramp...Ch. 6 - CP BIO Whiplash Injuries. When a car is hit from...Ch. 6 - CALC A net force along the x-axis that has...Ch. 6 - CALC Varying Coefficient of Friction. A box is...Ch. 6 - CALC Consider a spring that does not obey Hookes...Ch. 6 - CP A small block with Figure P6.71 a mass of...Ch. 6 - CALC Proton Bombardment. A proton with mass 1.67 ...Ch. 6 - You are asked to design spring bumpers for the...Ch. 6 - You and your bicycle have combined mass 80.0 kg....Ch. 6 - A 2.50-kg textbook is forced against a horizontal...Ch. 6 - The spring of a spring gun has force constant k =...Ch. 6 - One end of a horizontal spring with force constant...Ch. 6 - One end of a horizontal spring with force constant...Ch. 6 - A 5.00-kg block is moving at 0 = 6.00 m/s along a...Ch. 6 - A physics professor is pushed up a ramp inclined...Ch. 6 - Consider the system shown in Fig. P6.81. The rope...Ch. 6 - Consider the system shown in Fig. P6.81. The rope...Ch. 6 - On an essentially frictionless, horizontal ice...Ch. 6 - BIO All birds, independent of their size, must...Ch. 6 - A pump is required to lift 800 kg of water (about...Ch. 6 - The Grand Coulee Dam is 1270 m long and 170 m...Ch. 6 - A physics student spends part of her day walking...Ch. 6 - CALC An object has several forces acting on it....Ch. 6 - BIO Power of the Human Heart. The human heart is a...Ch. 6 - DATA Figure P6.90 shows the results of measuring...Ch. 6 - DATA In a physics lab experiment, one end of a...Ch. 6 - DATA For a physics lab experiment, four classmates...Ch. 6 - CALC A Spring with Mass. We usually ignore the...Ch. 6 - CALC An airplane in flight is subject to an air...Ch. 6 - BIO ENERGY OF LOCOMOTION. On flat ground, a 70-kg...Ch. 6 - BIO ENERGY OF LOCOMOTION. On flat ground, a 70-kg...Ch. 6 - BIO ENERGY OF LOCOMOTION. On flat ground, a 70-kg...
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- A block of mass m = 2.50 kg is pushed a distance d = 2.20 m along a frictionless, horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle = 25.0 below the horizontal as shown in Figure P6.3. Determine the work done on the block by (a) the applied force, (b) the normal force exerted by the table, (c) the gravitational force, and (d) the net force on the block. Figure P6.3arrow_forwardAs a young man, Tarzan climbed up a vine to reach his tree house. As he got older, he decided to build and use a staircase instead. Since the work of the gravitational force mg is path Independent, what did the King of the Apes gain in using stairs?arrow_forwardConsider a particle on which a force acts that depends on the position of the particle. This force is given by . Find the work done by this force when the particle moves from the origin to a point 5 meters to the right on the x-axis.arrow_forward
- If the net work done by external forces on a particle is zero, which of the following statements about the particle must be true? (a) Its velocity is zero. (b) Its velocity is decreased. (c) Its velocity is unchanged. (d) Its speed is unchanged. (e) More information is needed.arrow_forward(a) A force F=(4xi+3yj), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x direction from the origin to x = 5.00 m. Find the work W=Fdr done by the force on the object. (b) What If? Find the work W=Fdr done by the force on the object if it moves from the origin to (5.00 m, 5.00 m) along a straightline path making an angle of 45.0 with the positive x axis. Is the work done by this force dependent on the path taken between the initial and final points?arrow_forwardA shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 N frictional force. He pushes in a direction 25.0° below the horizontal. (a) What is the work done on the cart by friction? (b) What is the work done on the cart by the gravitational force? (c) What is the work done on the cart by the shopper? (d) Find the force the shopper exerts, using energy considerations. (e) What is the total work done on the cart?arrow_forward
- A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance?arrow_forwardRepeat the preceding problem, but this time, suppose that the work done by air resistance cannot be ignored. Let the work done by the air resistance when the skier goes from A to B along the given hilly path be —2000 J. The work done by air resistance is negative since the air resistance acts in the opposite direction to the displacement. Supposing the mass of the skier is 50 kg, what is the speed of the skier at point B ?arrow_forwardA force F = (6i 2j) N acts on a panicle that under-goes a displacement r = (3i + j) m. Find (a) the work done by the force on the particle and (b) the angle between F and r.arrow_forward
- The force acting on a particle varies as shown in Figure P6.14. Find the work done by the force on the particle as it moves (a) from x = 0 to x = 8.00 m, (b) from x = 8.00 m to x= 10.0 m, and (c) from x = 0 to x = 10.0 m.arrow_forwardGive an example of a situation in which there is a force and a displacement, but the force does no work. Explain why it does no work.arrow_forwardA particle moves in the xy plane (Fig. P9.30) from the origin to a point having coordinates x = 7.00 m and y = 4.00 m under the influence of a force given by F=3y2+x. a. What is the work done on the particle by the force F if it moves along path 1 (shown in red)? b. What is the work done on the particle by the force F if it moves along path 2 (shown in blue)? c. What is the work done on the particle by the force F if it moves along path 3 (shown in green)? d. Is the force F conservative or nonconservative? Explain. FIGURE P9.30 In each case, the work is found using the integral of Fdr along the path (Equation 9.21). W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz) (a) The work done along path 1, we first need to integrate along dr=dxi from (0,0) to (7,0) and then along dr=dyj from (7,0) to (7,4): W1=x=0;y=0x=7;y=0(3y2i+xj)(dxi)+x=7;y=0x=7;y=4(3y2i+xj)(dyj) Performing the dot products, we get W1=x=0;y=0x=7;y=03y2dx+x=7;y=0x=7;y=4xdy Along the first part of this path, y = 0 therefore the first integral equals zero. For the second integral, x is constant and can be pulled out of the integral, and we can evaluate dy. W1=0+x=7;y=0x=7;y=4xdy=xy|x=7;y=0x=7;y=4=28J (b) The work done along path 2 is along dr=dyj from (0,0) to (0,4) and then along dr=dxi from (0,4) to (7,4): W2=x=0;y=0x=0;y=4(3y2i+xj)(dyj)+x=0;y=4x=7;y=4(3y2i+xj)(dyi) Performing the dot product, we get: W2=x=0;y=0x=0;y=4xdy+x=0;y=4x=7;y=43y2dx Along the first part of this path, x = 0. Therefore, the first integral equals zero. For the second integral, y is constant and can be pulled out of the integral, and we can evaluate dx. W2=0+3y2x|x=0;y=4x=7;y=4=336J (c) To find the work along the third path, we first write the expression for the work integral. W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz)W=rtrf(3y2dx+xdy)(1) At first glance, this appears quite simple, but we cant integrate xdy=xy like we might have above because the value of x changes as we vary y (i.e., x is a function of y.) [In parts (a) and (b), on a straight horizontal or vertical line, only x or y changes]. One approach is to parameterize both x and y as a function of another variable, say t, and write each integral in terms of only x or y. Constraining dr to be along the desired line, we can relate dx and dy: tan=dydxdy=tandxanddx=dytan(2) Now, use equation (2) in (1) to express each integral in terms of only one variable. W=x=0;y=0x=7;y=43y2dx+x=0;y=0x=7;y=4xdyW=y=0y=43y2dytan+x=0x=7xtandx We can determine the tangent of the angle, which is constant (the angle is the angle of the line with respect to the horizontal). tan=4.007.00=0.570 Insert the value of the tangent and solve the integrals. W=30.570y33|y=0y=4+0.570x22|x=0x=7W=112+14=126J (d) Since the work done is not path-independent, this is non-conservative force. Figure P9.30ANSarrow_forward
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