Introductory Chemistry: An Active Learning Approach
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN: 9781305079250
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
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Chapter 6, Problem 46E
Interpretation Introduction

Interpretation:

The compound barium perchlorate forms a hydrate with three water molecules per formula unit. The name of hydrate and its formula is to be written.

Concept introduction:

Some chemical compounds on crystallization from water solution produce a crystal that contains water molecules as a part of their crystal structure. These water molecules of the crystals are called as water of crystallization or water of hydration. The crystal that results from the process of crystallization is referred as hydrate. Conversely, the water molecules can be driven away from the crystals by applying heat energy to afford anhydrous chemical compounds. The well-known example of a compound having water crystallization is CuSO4.5H2O. The anhydrous chemical compound CuSO4 (colorless) is combined with 5 H2O molecules on crystallization from a water solution result in hydrated CuSO4.5H2O (blue). The name of this chemical compound is denoted as copper (II) sulfate penta hydrate. In this case, the prefix ‘penta’ is usually referred as the presence of 5 molecules (water).

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Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100
Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.
For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table  and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.

Chapter 6 Solutions

Introductory Chemistry: An Active Learning Approach

Ch. 6 - Prob. 11ECh. 6 - Prob. 12ECh. 6 - Prob. 13ECh. 6 - CCl4, CBr4, NO, dinitrogen monoxide, sulfur...Ch. 6 - Prob. 15ECh. 6 - Write an equation that shows the formation of a...Ch. 6 - Prob. 17ECh. 6 - Prob. 18ECh. 6 - Prob. 19ECh. 6 - Prob. 20ECh. 6 - Prob. 21ECh. 6 - Prob. 22ECh. 6 - What are the names of AgBr, SnF2, Fe2O3, and...Ch. 6 - Prob. 24ECh. 6 - Prob. 25ECh. 6 - Prob. 26ECh. 6 - Prob. 27ECh. 6 - Prob. 28ECh. 6 - Prob. 29ECh. 6 - Fill in the blanks in the following table....Ch. 6 - Prob. 31ECh. 6 - Prob. 32ECh. 6 - What is the formula of sodium tellurate; what are...Ch. 6 - Prob. 34ECh. 6 - Explain how an anion can behave like an acid. Is...Ch. 6 - Prob. 36ECh. 6 - Prob. 37ECh. 6 - Prob. 38ECh. 6 - Prob. 39ECh. 6 - Prob. 40ECh. 6 - Among the following, identify all hydrates and...Ch. 6 - Prob. 42ECh. 6 - Prob. 43ECh. 6 - Prob. 44ECh. 6 - Prob. 45ECh. 6 - Prob. 46ECh. 6 - Prob. 47ECh. 6 - Prob. 48ECh. 6 - Prob. 49ECh. 6 - Prob. 50ECh. 6 - Prob. 51ECh. 6 - Prob. 52ECh. 6 - Prob. 53ECh. 6 - In each box, write the chemical formula of the...Ch. 6 - Prob. 55ECh. 6 - Prob. 56ECh. 6 - Prob. 57ECh. 6 - Prob. 58ECh. 6 - Prob. 59ECh. 6 - Prob. 60ECh. 6 - Prob. 61ECh. 6 - Prob. 62ECh. 6 - Prob. 63ECh. 6 - Prob. 64ECh. 6 - Prob. 65ECh. 6 - Prob. 66ECh. 6 - Prob. 67ECh. 6 - Prob. 68ECh. 6 - Prob. 69ECh. 6 - Prob. 70ECh. 6 - Prob. 71ECh. 6 - Prob. 72ECh. 6 - Prob. 73ECh. 6 - Prob. 74ECh. 6 - Prob. 75ECh. 6 - Prob. 76ECh. 6 - Prob. 77ECh. 6 - Prob. 78ECh. 6 - Prob. 79ECh. 6 - Prob. 80ECh. 6 - Prob. 81ECh. 6 - Prob. 82ECh. 6 - Prob. 83ECh. 6 - Prob. 84ECh. 6 - Prob. 85ECh. 6 - Prob. 86ECh. 6 - Prob. 1CLECh. 6 - Prob. 2CLECh. 6 - Prob. 3CLECh. 6 - Prob. 4CLECh. 6 - Prob. 1PECh. 6 - Prob. 2PECh. 6 - Prob. 3PECh. 6 - Prob. 4PECh. 6 - Prob. 5PECh. 6 - Prob. 6PECh. 6 - Prob. 7PECh. 6 - Prob. 8PECh. 6 - Prob. 9PECh. 6 - Prob. 10PECh. 6 - Prob. 11PECh. 6 - Prob. 12PECh. 6 - Prob. 13PECh. 6 - Prob. 14PECh. 6 - Prob. 15PECh. 6 - Prob. 16PECh. 6 - Prob. 17PE
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