
Interpretation:
The formulas of ammonium phosphate trihydrate and potassium sulfide pentahydrate is to be written
Concept introduction:
Some chemical compounds on crystallization from water solution produce a crystal that contains water molecules as a part of their crystal structure. These water molecules of the crystals are called as water of crystallization or water of hydration. The crystal that results from the process of crystallization is referred as hydrate. Conversely, the water molecules can be driven away from the crystals by applying heat energy to afford anhydrous chemical compounds. The well-known example of a compound having water crystallization is CuSO4.5H2O. The anhydrous chemical compound CuSO4 (colorless) is combined with 5 H2O molecules on crystallization from a water solution result in hydrated CuSO4.5H2O (blue). The name of this chemical compound is denoted as copper (II) sulfate penta hydrate. In this case, the prefix ‘penta’ is usually referred as the presence of 5 molecules (water).

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Chapter 6 Solutions
Introductory Chemistry: An Active Learning Approach
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- true or false,the equilibrium constant for this reaction is 0.50.PCI5(g) ↔ PCI3(g) + CI2(g)Based on the above, the equilibrium constant for the following reaction is 0.25.2PCI5(g) ↔. 2PCI3(g) + 2CI2(g)arrow_forwardtrue or false, using the following equilibrium, if carbon dioxide is added the equilibrium will shift toward the productsC(s) + CO2(g) ↔ 2CO(g)arrow_forward2S2O2/3- (aq) + I2 (aq) ---> S4O2/6- (aq) +2I- (aq) Experiment I2 (M) S2O3- (M) Initital Rate (M/s) 1 0.01 0.01 0.0004 2 0.01 0.02 0.0004 3 0.02 0.01 0.0008 Calculate the overall order for this reaction using the table data a) 3b) 0c) 2d) 1arrow_forward
- the decomposition of N2O5 is the first order with a half-life of 1.98 minutes. If the inital concentration of N2O5 is 0.200 M, what is the concentration after 6 minutes?a) 0.612 Mb) 0.035 Mc) 0.024 Md) 0.100 Marrow_forward20.00 mL of 0.150 M HCI is titrated with 0.075 M NaOH. What volume of NaOH is needed?a) 50 mLb) 20 mLc) 40 mLd) 26.66 mLarrow_forward20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCI. What is the molarity of the HCI?a) 0.150 Mb) 0.079 Mc) 0.025 Md) 0.050 Marrow_forward
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