14 Two battery-powered fan carts are resting on a frictionless horizontal track. The mass of cart A is twice the mass of cart B. The carts are released so they start moving to the right. Which answer and explanation correctly compare toe linear momentum of the carts after traveling the same distance? Assume that the force exerted by the air on the carts is the same for both carts and remains constant while the carts are moving. a. P A = P B because the sums of the forces exerted on the carts are equal. b. P A = P B because the distances traveled are equal. c. P A> P B because the air exerts a force on cart A for a longer time interval than on cart B. d. P A> P B because the heavier cart A pushes back on the air with a larger force than does cart B. e. P A < P B because the final velocity of can B is larger than the final velocity of cart A. f. P A < P B because can B has a larger acceleration than does can A.
14 Two battery-powered fan carts are resting on a frictionless horizontal track. The mass of cart A is twice the mass of cart B. The carts are released so they start moving to the right. Which answer and explanation correctly compare toe linear momentum of the carts after traveling the same distance? Assume that the force exerted by the air on the carts is the same for both carts and remains constant while the carts are moving. a. P A = P B because the sums of the forces exerted on the carts are equal. b. P A = P B because the distances traveled are equal. c. P A> P B because the air exerts a force on cart A for a longer time interval than on cart B. d. P A> P B because the heavier cart A pushes back on the air with a larger force than does cart B. e. P A < P B because the final velocity of can B is larger than the final velocity of cart A. f. P A < P B because can B has a larger acceleration than does can A.
14 Two battery-powered fan carts are resting on a frictionless horizontal track. The mass of cart A is twice the mass of cart B. The carts are released so they start moving to the right. Which answer and explanation correctly compare toe linear momentum of the carts after traveling the same distance? Assume that the force exerted by the air on the carts is the same for both carts and remains constant while the carts are moving.
a.
P
A
=
P
B
because the sums of the forces exerted on the carts are equal.
b.
P
A
=
P
B
because the distances traveled are equal.
c.
P
A>
P
B
because the air exerts a force on cart A for a longer time interval than on cart B.
d.
P
A>
P
B
because the heavier cart A pushes back on the air with a larger force than does cart B.
e.
P
A
<
P
B
because the final velocity of can B is larger than the final velocity of cart A.
f.
P
A
<
P
B
because can B has a larger acceleration than does can A.
For each of the actions depicted below, a magnet and/or metal loop moves with velocity v→ (v→ is constant and has the same magnitude in all parts). Determine whether a current is induced in the metal loop. If so, indicate the direction of the current in the loop, either clockwise or counterclockwise when seen from the right of the loop. The axis of the magnet is lined up with the center of the loop. For the action depicted in (Figure 5), indicate the direction of the induced current in the loop (clockwise, counterclockwise or zero, when seen from the right of the loop). I know that the current is clockwise, I just dont understand why. Please fully explain why it's clockwise, Thank you
A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).
What are the expected readings of the ammeter and voltmeter for the circuit in the figure below? (R = 5.60 Ω, ΔV = 6.30 V)
ammeter
I =
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