Chapter 6, Problem 124AP

Interpretation Introduction

Interpretation:

The color of the cesium flame emitting photon of given energy is to be determined, when a compound containing cesium ion is heated in a Bunsen burner flame.

Concept introduction:

The energy of a photon can be expressed as follows:

$\text{E}=\frac{\text{hc}}{\lambda }$

Here, E denotes the energy of a photon, $\text{h}$ denotes Planck’s constant $\left(6.63\times {10}^{-34}\text{ J}\cdot \text{s}\right)$, $\text{c}$ denotes the speed of light $\left(3.0\times {10}^8\text{ m/s}\right)$, and $\lambda$ denotes the wavelength.

Conversion of meter to nanometer is $\frac{1.00\text{ nm}}{1.00\times {10}^{-9}\text{ m}}$.