e % Transmittance 60 60 55- 50- 75 15 70- 70 65- 80 85 CHEMlab! OMNIC-[Window1] File Edit Collect View Process Analyze Report Window Help Experiment: D5 ATR - ZnSe (iD5 ATR ZnSe.exp) Expt Set Col Bkg Col Smp Tue Apr 01 16:50:47 2025 (GMT-04:00) 100 95 95 90 90- A M Open Save Print Stack Spe Full Sc Cmn Sci Aut Bsin Adv ATR Subtract Find Pks Selct Al Clear 3526.56 2935.32 4000 3500 3000 2500 2000 1500 Wavenumbers (cm-1) DeLL 1764.58 1637.85 1606.09 1463.49 1450.99 1431.10 6 Search Lib Mgr Prev Rpt Add NB View NB 1366.97 703.27 647.53 994.10 912.75 850.15 816.83 793.77 1232.00 1203.59 1147.94 1121.23 1033.66 1000 4:51 PM 4/1/2025 737.28 +4 X System Status Gas Chromatogram: 0000000 GC Integration: Retention Time Integration (min) 4.368 298214912 4.609 5.089 789959 38162066 5.430 1426047

e % Transmittance 60 60 55- 50- 75 15 70- 70 65- 80 85 CHEMlab! OMNIC-[Window1] File Edit Collect View Process Analyze Report Window Help Experiment: D5 ATR - ZnSe (iD5 ATR ZnSe.exp) Expt Set Col Bkg Col Smp Tue Apr 01 16:50:47 2025 (GMT-04:00) 100 95 95 90 90- A M Open Save Print Stack Spe Full Sc Cmn Sci Aut Bsin Adv ATR Subtract Find Pks Selct Al Clear 3526.56 2935.32 4000 3500 3000 2500 2000 1500 Wavenumbers (cm-1) DeLL 1764.58 1637.85 1606.09 1463.49 1450.99 1431.10 6 Search Lib Mgr Prev Rpt Add NB View NB 1366.97 703.27 647.53 994.10 912.75 850.15 816.83 793.77 1232.00 1203.59 1147.94 1121.23 1033.66 1000 4:51 PM 4/1/2025 737.28 +4 X System Status Gas Chromatogram: 0000000 GC Integration: Retention Time Integration (min) 4.368 298214912 4.609 5.089 789959 38162066 5.430 1426047

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter14: Chromatography

Section: Chapter Questions

Problem 9P

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Similar questions

What is the relative average deviation in the following percent KHP values in ppt? 46.80% 47.23% 48.03%
(81310 - 76200) ÷ 0.00216 With Sig Figs
2. A gas chromatogram of a four-(4)-component mixture had the following areas and retention times (RT). Component ABCD (RT) (min) 2.564 5.241 1.904 3.217 Area (mm²) 2341 1278 4302 1987 A. Which compound do you suspect is the most volatile? Why? B. Calculate the percent composition of component D.
how can i plot this data with a regression line and including r^2 term?
Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
Can paper chromatography be used to separate and identify very volatile substances? How do I prove this.
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A student was performing paper chromatography and let the separation continue overnight. Thestudent wished to determine if the mixture contained a substance with an Rf factor of 0.343 where:Rf = (distance travelled by the component)/(distance travelled by the solvent)a) What data would be affected by this error?b) Explain the effect on the calculated Rf.
What is the relative average deviation in the following percent KHP values in ppt? (Enter your answer as a number without units.) 46.89 % 47.51 % 47.92 %
50 Percentage Red No. 40 Soln 100% 80% 60% 40% Table 4.1: Dilutions of Red No. 40 & Absorbance Volume of Red No. 40 Soln (mL) 10me 8mL опи 4mL Percentage Red No. 40 Soln 100% 80% 60% 40% 20% Volume of DI Water (mL) OML 2mL LIML M UML 8ML Table 4.2: Dilutions of Red No. 40 & Absorbance Concentration Red No. 40 2. Report the wavelength with the maximum absorbance of Red No. 40 dye. Absorbance 20% 2ML Part A: Making a Calibration Curve for Beer's Law 1. Calculate the concentrations of each of your diluted Red No. 40 solutions and add these to Table 4.2. Show at least one sample calculation in the space below. 0.251 0.192 Total Volume 0.181 0·119 0.060 (mL) 10 mL 10 mL 10 mL 10 mL 10 mL
A new method for the analysis of mercury was in an ore sample was tested and obtained the following data: Trial % Hg 1 12.76 2 12.57 3 12.72 4 12.79 5 12.76 Average: 12.72 St. Deviation: 0.08746 The standard method for mercury analysis was also used to test the ore. Is the mean value of the new method significantly different from the mean value of the accepted value at the 95% confidence interval? You may assume the standard deviations are the same. Accepted Method Results # of samples = 6 Average = 12.63% Hg Standard deviation = 0.053