Chapter 6, Problem 10CTQ

Consider the Newman projection below.
a. Draw a full Lewis structure of this molecule with ${\text{R}}_{\text{1}}=\text{Me},{\text{R}}_{\text{2}}=\text{Et}$ , and ${\text{R}}_{\text{3}}=i-\text{Pr}$ .
b. Given the sizes of these R groups $\left({\text{R}}_{\text{3}}>{\text{R}}_{\text{2}}>{\text{R}}_{\text{1}}\right)$ , does the Newman projection above show thelowest potential energy conformation of this bond? If not, draw a Newman projectionshowing the lowest P.E. conformation (sighting down this same bond).
c. To draw a Newman projection in the lowest P.E. conformation, the following rule of thumbusually applies: Place the largest group on the front carbon anti to the largest group on theback carbon. Is your answer to the previous question consistent with this rule of thumb?