Concept explainers
Todetermine:The equation an architect can enter to represent a second beamwhose graph will pass through the corner at
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Answer to Problem 4P
The architecture can enter the equation
Explanation of Solution
Given information:
The graph of second beampasses through the corner at
Formulaused:
The equation of line with slope m and that makes intercept of length
Calculations:
Let OA is the existing beam and CB the beam parallel to the existing beam but passing through corner
Suppose equation of existing beam (line) that makes angle
Then equation of beam (line) CB that is parallel to beam OA is
Therefore, equation of second beam that architect can enter is
In the graphs shown in Figure-1,
Hence, for the structure shown in Figure-1, the architecture can enter the equation
Conclusion:
For the structure shown in Figure-1, the architecture can enter the equation
Chapter 5 Solutions
High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9
Additional Math Textbook Solutions
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Precalculus
College Algebra with Modeling & Visualization (5th Edition)
Calculus: Early Transcendentals (2nd Edition)
Elementary Statistics (13th Edition)
Algebra and Trigonometry (6th Edition)
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