EBK FUNDAMENTALS OF APPLIED ELECTROMAGN
7th Edition
ISBN: 8220100663659
Author: ULABY
Publisher: PEARSON
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Chapter 5.3, Problem 9CQ
To determine
The followability of
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Calcule las integrales de línea vectorial F * dr de los vectoriales dados
A) El campo vectorial F(x y)=(xy y) siendo C la cuarta parte de la circunferencia 16=x2+y2 como se muestra en la figura
Solve the given integral when c is a perfect circle to get a relation between H vector and I .
Obtain the differential equation of all the
circles with center on line y - x and passing
through the origin.
%3D
Select one:
O a.
(y² + 2xy – x²)dx – (y² – 2xy² – x²)dy = 0
O b.
(y² – 2xy – x²)dx – (y² – 2xy – x²)dy = 0
O C.
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(y² + 2xy - x²)dx+ (y² – 2xy- x²)dy = 0
O d.
(y2 + 2xy- x²)dx - (y²- 2xy +x²)dy = 0
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Chapter 5 Solutions
EBK FUNDAMENTALS OF APPLIED ELECTROMAGN
Ch. 5.1 - What are the major differences between the...Ch. 5.1 - Prob. 2CQCh. 5.1 - How is the direction of the magnetic moment of a...Ch. 5.1 - If one of two wires of equal length is formed into...Ch. 5.1 - An electron moving in the positive x direction...Ch. 5.1 - A proton moving with a speed of 2 106 m/s through...Ch. 5.1 - A charged particle with velocity u is moving in a...Ch. 5.1 - A horizontal wire with a mass per unit length of...Ch. 5.1 - A square coil of 100 turns and 0.5 m long sides is...Ch. 5.2 - Two infinitely long parallel wires carry currents...
Ch. 5.2 - Devise a right-hand rule for the direction of the...Ch. 5.2 - What is a magnetic dipole? Describe its magnetic...Ch. 5.2 - Prob. 6ECh. 5.2 - A wire carrying a current of 4 A is formed into a...Ch. 5.2 - Prob. 8ECh. 5.3 - What are the fundamental differences between...Ch. 5.3 - Prob. 9CQCh. 5.3 - Compare the utility of applying the BiotSavart law...Ch. 5.3 - Prob. 11CQCh. 5.3 - A current I flows in the inner conductor of a long...Ch. 5.3 - The metal niobium becomes a superconductor with...Ch. 5.5 - What are the three types of magnetic materials and...Ch. 5.5 - What causes magnetic hysteresis in ferromagnetic...Ch. 5.5 - Prob. 14CQCh. 5.5 - The magnetic vector M is the vector sum of the...Ch. 5.6 - With reference to Fig. 5-24, determine the single...Ch. 5.7 - Prob. 15CQCh. 5.7 - What is the difference between self-inductance and...Ch. 5.7 - Prob. 17CQCh. 5.7 - Use Eq. (5.89) to obtain an expression for B at a...Ch. 5 - An electron with a speed of 8 106 m/s is...Ch. 5 - When a particle with charge q and mass m is...Ch. 5 - The circuit shown in Fig. P5.3 uses two identical...Ch. 5 - The rectangular loop shown in Fig. P5.4 consists...Ch. 5 - In a cylindrical coordinate system, a 2 m long...Ch. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - The loop shown in Fig. P5.9 consists of radial...Ch. 5 - An infinitely long, thin conducting sheet defined...Ch. 5 - An infinitely long wire carrying a 25 A current in...Ch. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - A circular loop of radius a carrying current I1 is...Ch. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Three long, parallel wires are arranged as shown...Ch. 5 - A square loop placed as shown in Fig. P5.20 has 2...Ch. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Repeat Problem 5.22 for a current density J=zJ0er.Ch. 5 - In a certain conducting region, the magnetic field...Ch. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - A uniform current density given by J=zj0 (A/m2)...Ch. 5 - A thin current element extending between z = L/2...Ch. 5 - In the model of the hydrogen atom proposed by Bohr...Ch. 5 - Iron contains 8.5 1028 atoms/m3. At saturation,...Ch. 5 - The xy plane separates two magnetic media with...Ch. 5 - Given that a current sheet with surface current...Ch. 5 - In Fig. P5.34, the plane defined by x y = 1...Ch. 5 - The plane boundary defined by z = 0 separates air...Ch. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - A solenoid with a length of 20 cm and a radius of...Ch. 5 - Prob. 39PCh. 5 - The rectangular loop shown in Fig. P5.40 is...Ch. 5 - Determine the mutual inductance between the...
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The Divergence Theorem; Author: Professor Dave Explains;https://www.youtube.com/watch?v=vZGvgru4TwE;License: Standard Youtube License