Interpretation:
The structural formulas of the two isomeric bromides formed in the reaction of
Concept introduction:
Secondary alcohols undergo nucleophilic substitution via a modified
An
The nucleophile can then attack the planar carbocation from below the plane as well as from above the plane, leading to a racemic mixture of products.
The product with inverted symmetry is generally favored because the proximity of the water molecule and the carbocation formed in the first step hampers the attack of nucleophile from that face.
For an optically active alcohol with more than one chirality centers, only the absolute configuration at the carbon atom bearing the hydroxyl group changes while the absolute configuration at the other chiral center remains the same.
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- Account for the regioselectivity and stereoselectivity observed when this compound is treated with Br2 in H₂O by drawing the final product in the reaction. • Use wedge and hash bonds ONLY when needed to show reaction stereochemistry. • If the reaction produces a racemic mixture, just draw one stereoisomer.arrow_forwardCompound A Br₂, H₂O Compound B (C8H15BrO) + enantiomer CH₂O O Compound C + enantiomer Draw the structure of Compound B (watch out for stereochemistry), and mechanisms for its formation from Compound A, and its conversion to Compound C.arrow_forwardPredict the structure (stereochemistry) of the dibromide products of a synaddition of bromine to trans-cinnamic acid. Predict the structure (stereochemistry) of the dibromide products of an antiaddition of bromine to trans-cinnamic acid.Label each product as threo or erytho.It may be helpful to construct molecular models of threo-and erytho-2,3-dibromo-3-phenylpropanioc acid.arrow_forward
- 1,3,5,7-Cyclooctatetraene, CgHg, is an unusual hydrocarbon in that it reacts with exactly 2 equivalents of potassium to give A, CgHgK₂, which can be isolated as a white solid. A exhibits a single proton NMR signal. Draw the structure of A. 1,3,5,7-cycloctatetraene 2 K/THF C8H8K2 + H₂ A • Draw cations and anions in separate sketchers. Separate structures with + signs from the drop-down menu. ? n ChemDoodle®arrow_forwardDraw the structures for (Z)-3-methylhex-3-ene and the two major organic products for its reaction with HBr. Be sure to show all stereoisomers using wedge and dash stereochemistry at any chirality center.arrow_forwardCompound A has the formula C₂H₁9Cl. B is a C₂H19Br compound. A and B undergo base-promoted E2 elimination to give the same alkene C as the major product as well as different minor products. C reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2,6-dimethylheptane. Addition of HCI to C yields A as the major product. Propose structures for A and B. • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. ● ▾ *%-85 ChemDoodle Qt Jn [F 116arrow_forward
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- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning