The possible orbitals in an atom should be determined. Concept Introduction: The distribution of electrons in an atom is described by the use of quantum numbers used by the Bohr model one-dimensional model. The most important information that is the size of the atom is determined by the principal quantum number denoted by symbol n . Other quantum numbers are angular and magnetic quantum numbers which describes shape and orientation in the space of the orbitals of the atom. The forth quantum number is spin quantum number which is denoted by symbol s and determined the spin of the electron if it is clockwise or anticlockwise. The all four quantum numbers are explained in detail as follows: Principal quantum number (n) determines the size of the orbital. The orbital with principal quantum number 2 is larger than the value 1. This also determines the energy of the orbital, as the value of n increases the energy of the orbital increases as its distance from the nucleus increases. Angular quantum number (l) determined the shape of the orbital. For l = 0 , the shape of the orbital is sphere, for l = 1 , the shape of orbital is polar and that for l = 2 is cloverleaf. The rules for the allowed quantum numbers combinations are as follows: All the three quantum numbers ( n, l and m ) describes the orbital of an atom and they are integers. The principal quantum number, n value cannot be zero. Thus, the values allowed for the principal quantum number are 1, 2, 3, 4, and so on. The value of angular quantum number, l can be between 0 to n-1. Thus, if value of n is equal to 3 the value of l can be 0, 1 or 2. The value of magnetic quantum number, m can be between − l to +l . Thus, if value of l is equal to 2, m can be wither -2, -1, 0, +1, or +2 lFor same number of principal quantum number, an orbital form a shell. The first character denotes the shell and the second identifies the sub-shell. Here, for s orbital value of l = 0 , for p orbital it is l = 1 , for d orbital it is l = 2 and for f it is 3.

Question

Want to see the full answer?

Answer 1

Question

Chapter 5, Problem 90APP

Interpretation Introduction

Interpretation: The possible orbitals in an atom should be determined.

Concept Introduction: The distribution of electrons in an atom is described by the use of quantum numbers used by the Bohr model one-dimensional model. The most important information that is the size of the atom is determined by the principal quantum number denoted by symbol n . Other quantum numbers are angular and magnetic quantum numbers which describes shape and orientation in the space of the orbitals of the atom.

The forth quantum number is spin quantum number which is denoted by symbol s and determined the spin of the electron if it is clockwise or anticlockwise.

The all four quantum numbers are explained in detail as follows:

Principal quantum number (n) determines the size of the orbital. The orbital with principal quantum number 2 is larger than the value 1. This also determines the energy of the orbital, as the value of n increases the energy of the orbital increases as its distance from the nucleus increases.

Angular quantum number (l) determined the shape of the orbital. For l=0 , the shape of the orbital is sphere, for l=1 , the shape of orbital is polar and that for l=2 is cloverleaf.

The rules for the allowed quantum numbers combinations are as follows:

All the three quantum numbers ( n, l and m ) describes the orbital of an atom and they are integers.

The principal quantum number, n value cannot be zero. Thus, the values allowed for the principal quantum number are 1, 2, 3, 4, and so on.
The value of angular quantum number, l can be between 0 to n-1. Thus, if value of n is equal to 3 the value of l can be 0, 1 or 2.
The value of magnetic quantum number, m can be between − l to +l . Thus, if value of l is equal to 2, m can be wither -2, -1, 0, +1, or +2

lFor same number of principal quantum number, an orbital form a shell. The first character denotes the shell and the second identifies the sub-shell.

Here, for s orbital value of l=0 , for p orbital it is l=1 , for d orbital it is l=2 and for f it is 3.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Protecting Groups and Carbonyls 6) The synthesis generates allethrolone that exhibits high insect toxicity but low mammalian toxicity. They are used in pet shampoo, human lice shampoo, and industrial sprays for insects and mosquitos. Propose detailed mechanistic steps to generate the allethrolone label the different types of reagents (Grignard, acid/base protonation, acid/base deprotonation, reduction, oxidation, witting, aldol condensation, Robinson annulation, etc.) III + VI HS HS H+ CH,CH,Li III I II IV CI + P(Ph)3 V ༼ Hint: no strong base added VI S VII IX HO VIII -MgBr HgCl2,HgO HO. isomerization aqeuous solution H,SO, ༽༽༤༽༽ X MeOH Hint: enhances selectivity for reaction at the S X ☑

Draw the complete mechanism for the acid-catalyzed hydration of this alkene. esc 田 Explanation Check 1 888 Q A slock Add/Remove step Q F4 F5 F6 A བྲA F7 $ % 5 @ 4 2 3 & 6 87 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce W E R T Y U S D LL G H IK DD 요 F8 F9 F10 F1 * ( 8 9 0 O P J K L Z X C V B N M H He command

Explanation Check F1 H₂O H₂ Pd 1) MCPBA 2) H3O+ 1) Hg(OAc)2, H₂O 2) NaBH4 OH CI OH OH OH hydration halohydrin formation addition halogenation hydrogenation inhalation hydrogenation hydration ☐ halohydrin formation addition halogenation formation chelation hydrogenation halohydrin formation substitution hydration halogenation addition Ohalohydrin formation subtraction halogenation addition hydrogenation hydration F2 80 F3 σ F4 F5 F6 1 ! 2 # 3 $ 4 % 05 Q W & Å © 2025 McGraw Hill LLC. All Rights Reserved. F7 F8 ( 6 7 8 9 LU E R T Y U A F9