Explanation The required reaction is given below. 2 H C l ( g ) ⇌ H 2 ( g ) + C l 2 ( s ) , K = 3.2 × 10 − 34 The expression for equilibrium constant for the above reaction can be written as shown below, K = ( P H 2 ) ( P C l 2 ) ( P H C l ) 2 Given that, the initial partial pressure of H C l is 0.22 b a r . An equilibrium table can be set up as given below. C o m p o s i t i o n ( b a r ) H C l H 2 C l 2 I n i t i a l p r e s s u r e 0.22 0 0 C h a n g e i n p r e s s u r e − 2 x + x + x E q u i l i b r i u m p r e s s u r e 0.22 − 2 x x x Now, these values in the fourth row can be inserted in the equilibrium constant expression as shown below. K = ( x ) ( x ) ( 0.22 − 2 x ) 2 By assuming x ≪ 0.22 , it can be written that 0.22 − x ≈ 0.22. Now, the above equilibrium expression can be solved for x . K = ( x ) ( x ) ( 0.22 − 2 x ) 2 ≈ ( x ) ( x ) ( 0.22 ) 2 3

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ISBN: 9781319086411

Author: ATKINS

Publisher: MAC HIGHER

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Chapter 5, Problem 5I.29E

Interpretation Introduction

Interpretation:

The equilibrium partial pressures of HCl, H2, and Cl2 has to be calculated. The reaction is given below.

2HCl(g)⇌H2(g)+Cl2(s), K=3.2×10−34

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Chapter 5, Problem 5I.28E

Chapter 5, Problem 5I.30E

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Chapter 5 Solutions

CHEMICAL PRINCIPLES PKG W/SAPLING

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The equilibrium partial pressures of H C l , H 2 , a n d C l 2 has to be calculated. The reaction is given below. 2 H C l ( g ) ⇌ H 2 ( g ) + C l 2 ( s ) , K = 3.2 × 10 − 34

Solution Summary: The author explains how the equilibrium partial pressures of HCl,h_2,&>Cl have to be calculated. An equilibrium table can be set up.

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Interpretation:

The equilibrium partial pressures of HCl, H2, and Cl2 has to be calculated. The reaction is given below.

2HCl(g)⇌H2(g)+Cl2(s), K=3.2×10−34

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Chapter 5 Solutions

The equilibrium partial pressures of H C l , H 2 , a n d C l 2 has to be calculated. The reaction is given below. 2 H C l ( g ) ⇌ H 2 ( g ) + C l 2 ( s ) , K = 3.2 × 10 − 34

Solution Summary: The author explains how the equilibrium partial pressures of HCl,h_2,&>Cl­ have to be calculated. An equilibrium table can be set up.

Videos

Interpretation: The equilibrium partial pressures of HCl, H2, and Cl2 has to be calculated. The reaction is given below. 2HCl(g)⇌H2(g)+Cl2(s), K=3.2×10−34

Want to see the full answer?

Chapter 5 Solutions

Solution Summary: The author explains how the equilibrium partial pressures of HCl,h_2,&>Cl have to be calculated. An equilibrium table can be set up.

Interpretation:

The equilibrium partial pressures of HCl, H2, and Cl2 has to be calculated. The reaction is given below.

2HCl(g)⇌H2(g)+Cl2(s), K=3.2×10−34