Explanation The required reaction is given below. 2 P C l 5 ( g ) ⇌ P C l 3 ( g ) + C l 2 ( g ) , K = 25 The expression for equilibrium constant for the above reaction can be written as shown below, K = ( P P C l 3 ) ( P C l 2 ) ( P P C l 5 ) 2 Given that, the equilibrium partial pressures of P C l 5 a n d C l 2 is 1.18 b a r a n d 5.43 b a r respectively. By rearranging the above expression, the equilibrium partial pressure of P C l 5 can be calculated as shown below

7th Edition

ISBN: 9781319086411

Author: ATKINS

Publisher: MAC HIGHER

See similar textbooks

Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to a…

Videos

Question

Chapter 5, Problem 5I.5E

Interpretation Introduction

Interpretation:

The equilibrium partial pressure of PCl3 at 500 K for the given below reaction has to be calculated.

2PCl5(g)⇌PCl3(g)+Cl2(g), K=25

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 5, Problem 5I.4E

Chapter 5, Problem 5I.6E

Students have asked these similar questions

10. The main product of the following reaction is [1.1:4',1"-terphenyl]-2'-yl(1h-pyrazol-4- yl)methanone Ph N-H Ph

Draw the Fischer projection for a D-aldo-pentose. (aldehyde pentose). How many total stereoisomers are there? Name the sugar you drew. Draw the Fischer projection for a L-keto-hexose. (ketone pentose). How many total stereoisomers are there? Draw the enantiomer.

Draw a structure using wedges and dashes for the following compound: H- Et OH HO- H H- Me OH

Chapter 5 Solutions

CHEMICAL PRINCIPLES PKG W/SAPLING

Ch. 5 - Prob. 5A.1AST Ch. 5 - Prob. 5A.1BST Ch. 5 - Prob. 5A.2AST Ch. 5 - Prob. 5A.2BST Ch. 5 - Prob. 5A.3AST Ch. 5 - Prob. 5A.3BST Ch. 5 - Prob. 5A.1E Ch. 5 - Prob. 5A.2E Ch. 5 - Prob. 5A.3E Ch. 5 - Prob. 5A.4E

Ch. 5 - Prob. 5A.5E Ch. 5 - Prob. 5A.6E Ch. 5 - Prob. 5A.7E Ch. 5 - Prob. 5A.8E Ch. 5 - Prob. 5A.11E Ch. 5 - Prob. 5B.1AST Ch. 5 - Prob. 5B.1BST Ch. 5 - Prob. 5B.2AST Ch. 5 - Prob. 5B.2BST Ch. 5 - Prob. 5B.3AST Ch. 5 - Prob. 5B.3BST Ch. 5 - Prob. 5B.1E Ch. 5 - Prob. 5B.2E Ch. 5 - Prob. 5B.3E Ch. 5 - Prob. 5B.5E Ch. 5 - Prob. 5B.7E Ch. 5 - Prob. 5C.1AST Ch. 5 - Prob. 5C.1BST Ch. 5 - Prob. 5C.2AST Ch. 5 - Prob. 5C.2BST Ch. 5 - Prob. 5C.3AST Ch. 5 - Prob. 5C.3BST Ch. 5 - Prob. 5C.1E Ch. 5 - Prob. 5C.3E Ch. 5 - Prob. 5C.4E Ch. 5 - Prob. 5C.5E Ch. 5 - Prob. 5C.6E Ch. 5 - Prob. 5C.7E Ch. 5 - Prob. 5C.8E Ch. 5 - Prob. 5C.9E Ch. 5 - Prob. 5C.10E Ch. 5 - Prob. 5C.11E Ch. 5 - Prob. 5C.12E Ch. 5 - Prob. 5C.15E Ch. 5 - Prob. 5C.16E Ch. 5 - Prob. 5D.1AST Ch. 5 - Prob. 5D.1BST Ch. 5 - Prob. 5D.1E Ch. 5 - Prob. 5D.2E Ch. 5 - Prob. 5D.3E Ch. 5 - Prob. 5D.4E Ch. 5 - Prob. 5D.5E Ch. 5 - Prob. 5D.6E Ch. 5 - Prob. 5D.7E Ch. 5 - Prob. 5D.8E Ch. 5 - Prob. 5D.9E Ch. 5 - Prob. 5D.10E Ch. 5 - Prob. 5D.11E Ch. 5 - Prob. 5D.12E Ch. 5 - Prob. 5D.13E Ch. 5 - Prob. 5D.14E Ch. 5 - Prob. 5D.15E Ch. 5 - Prob. 5D.16E Ch. 5 - Prob. 5D.18E Ch. 5 - Prob. 5D.19E Ch. 5 - Prob. 5D.20E Ch. 5 - Prob. 5E.1AST Ch. 5 - Prob. 5E.1BST Ch. 5 - Prob. 5E.2AST Ch. 5 - Prob. 5E.2BST Ch. 5 - Prob. 5E.1E Ch. 5 - Prob. 5E.2E Ch. 5 - Prob. 5E.11E Ch. 5 - Prob. 5E.12E Ch. 5 - Prob. 5F.1AST Ch. 5 - Prob. 5F.1BST Ch. 5 - Prob. 5F.2AST Ch. 5 - Prob. 5F.2BST Ch. 5 - Prob. 5F.3AST Ch. 5 - Prob. 5F.3BST Ch. 5 - Prob. 5F.4AST Ch. 5 - Prob. 5F.4BST Ch. 5 - Prob. 5F.5AST Ch. 5 - Prob. 5F.5BST Ch. 5 - Prob. 5F.1E Ch. 5 - Prob. 5F.2E Ch. 5 - Prob. 5F.3E Ch. 5 - Prob. 5F.5E Ch. 5 - Prob. 5F.7E Ch. 5 - Prob. 5F.9E Ch. 5 - Prob. 5F.10E Ch. 5 - Prob. 5F.11E Ch. 5 - Prob. 5F.12E Ch. 5 - Prob. 5F.13E Ch. 5 - Prob. 5F.14E Ch. 5 - Prob. 5F.15E Ch. 5 - Prob. 5F.16E Ch. 5 - Prob. 5G.1AST Ch. 5 - Prob. 5G.1BST Ch. 5 - Prob. 5G.2AST Ch. 5 - Prob. 5G.2BST Ch. 5 - Prob. 5G.3AST Ch. 5 - Prob. 5G.3BST Ch. 5 - Prob. 5G.4AST Ch. 5 - Prob. 5G.4BST Ch. 5 - Prob. 5G.5AST Ch. 5 - Prob. 5G.5BST Ch. 5 - Prob. 5G.1E Ch. 5 - Prob. 5G.2E Ch. 5 - Prob. 5G.3E Ch. 5 - Prob. 5G.4E Ch. 5 - Prob. 5G.7E Ch. 5 - Prob. 5G.8E Ch. 5 - Prob. 5G.9E Ch. 5 - Prob. 5G.11E Ch. 5 - Prob. 5G.12E Ch. 5 - Prob. 5G.13E Ch. 5 - Prob. 5G.14E Ch. 5 - Prob. 5G.15E Ch. 5 - Prob. 5G.16E Ch. 5 - Prob. 5G.17E Ch. 5 - Prob. 5G.19E Ch. 5 - Prob. 5G.20E Ch. 5 - Prob. 5G.21E Ch. 5 - Prob. 5G.22E Ch. 5 - Prob. 5H.1AST Ch. 5 - Prob. 5H.1BST Ch. 5 - Prob. 5H.2AST Ch. 5 - Prob. 5H.2BST Ch. 5 - Prob. 5H.1E Ch. 5 - Prob. 5H.2E Ch. 5 - Prob. 5H.3E Ch. 5 - Prob. 5H.4E Ch. 5 - Prob. 5H.5E Ch. 5 - Prob. 5H.6E Ch. 5 - Prob. 5I.1AST Ch. 5 - Prob. 5I.1BST Ch. 5 - Prob. 5I.2AST Ch. 5 - Prob. 5I.2BST Ch. 5 - Prob. 5I.3AST Ch. 5 - Prob. 5I.3BST Ch. 5 - Prob. 5I.4AST Ch. 5 - Prob. 5I.4BST Ch. 5 - Prob. 5I.1E Ch. 5 - Prob. 5I.2E Ch. 5 - Prob. 5I.3E Ch. 5 - Prob. 5I.4E Ch. 5 - Prob. 5I.5E Ch. 5 - Prob. 5I.6E Ch. 5 - Prob. 5I.7E Ch. 5 - Prob. 5I.9E Ch. 5 - Prob. 5I.10E Ch. 5 - Prob. 5I.11E Ch. 5 - Prob. 5I.12E Ch. 5 - Prob. 5I.13E Ch. 5 - Prob. 5I.14E Ch. 5 - Prob. 5I.15E Ch. 5 - Prob. 5I.16E Ch. 5 - Prob. 5I.17E Ch. 5 - Prob. 5I.18E Ch. 5 - Prob. 5I.19E Ch. 5 - Prob. 5I.20E Ch. 5 - Prob. 5I.21E Ch. 5 - Prob. 5I.22E Ch. 5 - Prob. 5I.23E Ch. 5 - Prob. 5I.24E Ch. 5 - Prob. 5I.25E Ch. 5 - Prob. 5I.26E Ch. 5 - Prob. 5I.27E Ch. 5 - Prob. 5I.28E Ch. 5 - Prob. 5I.29E Ch. 5 - Prob. 5I.30E Ch. 5 - Prob. 5I.32E Ch. 5 - Prob. 5I.33E Ch. 5 - Prob. 5I.34E Ch. 5 - Prob. 5I.35E Ch. 5 - Prob. 5I.36E Ch. 5 - Prob. 5J.1AST Ch. 5 - Prob. 5J.1BST Ch. 5 - Prob. 5J.3AST Ch. 5 - Prob. 5J.3BST Ch. 5 - Prob. 5J.4AST Ch. 5 - Prob. 5J.4BST Ch. 5 - Prob. 5J.5AST Ch. 5 - Prob. 5J.5BST Ch. 5 - Prob. 5J.1E Ch. 5 - Prob. 5J.2E Ch. 5 - Prob. 5J.3E Ch. 5 - Prob. 5J.4E Ch. 5 - Prob. 5J.5E Ch. 5 - Prob. 5J.6E Ch. 5 - Prob. 5J.9E Ch. 5 - Prob. 5J.10E Ch. 5 - Prob. 5J.11E Ch. 5 - Prob. 5J.12E Ch. 5 - Prob. 5J.13E Ch. 5 - Prob. 5J.17E Ch. 5 - Prob. 5.1E Ch. 5 - Prob. 5.2E Ch. 5 - Prob. 5.3E Ch. 5 - Prob. 5.4E Ch. 5 - Prob. 5.5E Ch. 5 - Prob. 5.6E Ch. 5 - Prob. 5.7E Ch. 5 - Prob. 5.8E Ch. 5 - Prob. 5.9E Ch. 5 - Prob. 5.10E Ch. 5 - Prob. 5.11E Ch. 5 - Prob. 5.12E Ch. 5 - Prob. 5.13E Ch. 5 - Prob. 5.14E Ch. 5 - Prob. 5.15E Ch. 5 - Prob. 5.16E Ch. 5 - Prob. 5.17E Ch. 5 - Prob. 5.19E Ch. 5 - Prob. 5.23E Ch. 5 - Prob. 5.24E Ch. 5 - Prob. 5.25E Ch. 5 - Prob. 5.26E Ch. 5 - Prob. 5.27E Ch. 5 - Prob. 5.28E Ch. 5 - Prob. 5.29E Ch. 5 - Prob. 5.30E Ch. 5 - Prob. 5.31E Ch. 5 - Prob. 5.32E Ch. 5 - Prob. 5.33E Ch. 5 - Prob. 5.35E Ch. 5 - Prob. 5.37E Ch. 5 - Prob. 5.38E Ch. 5 - Prob. 5.41E Ch. 5 - Prob. 5.43E Ch. 5 - Prob. 5.44E Ch. 5 - Prob. 5.45E Ch. 5 - Prob. 5.46E Ch. 5 - Prob. 5.47E Ch. 5 - Prob. 5.49E Ch. 5 - Prob. 5.51E Ch. 5 - Prob. 5.53E Ch. 5 - Prob. 5.55E Ch. 5 - Prob. 5.57E Ch. 5 - Prob. 5.58E Ch. 5 - Prob. 5.61E Ch. 5 - Prob. 5.62E

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

The equilibrium partial pressure of P C l 3 at 500 K for the given below reaction has to be calculated. 2 P C l 5 ( g ) ⇌ P C l 3 ( g ) + C l 2 ( g ) , K = 25

Solution Summary: The author explains that the equilibrium partial pressure of PCl_3 at 500K for the given below reaction has to be calculated.

Concept explainers

Videos

Interpretation:

The equilibrium partial pressure of PCl3 at 500 K for the given below reaction has to be calculated.

2PCl5(g)⇌PCl3(g)+Cl2(g), K=25

Want to see the full answer?

Chapter 5 Solutions

The equilibrium partial pressure of P C l 3 at 500 K for the given below reaction has to be calculated. 2 P C l 5 ( g ) ⇌ P C l 3 ( g ) + C l 2 ( g ) , K = 25

Solution Summary: The author explains that the equilibrium partial pressure of PCl_3 at 500K for the given below reaction has to be calculated.

Concept explainers

Videos

Interpretation: The equilibrium partial pressure of PCl3 at 500 K for the given below reaction has to be calculated. 2PCl5(g)⇌PCl3(g)+Cl2(g), K=25

Want to see the full answer?

Chapter 5 Solutions

Interpretation:

The equilibrium partial pressure of PCl3 at 500 K for the given below reaction has to be calculated.

2PCl5(g)⇌PCl3(g)+Cl2(g), K=25