Chapter 5, Problem 5G.5AST

Interpretation Introduction

Interpretation:

The value of $\text{K}$ has to be determined using the value of ${\text{ΔG}}_{\text{r}}{}^{\text{o}}$ for the given reaction.

  ${\text{N}}_{\text{2}}{\text{O}}_{\text{4}}\text{(g)}\to \text{2}{\text{NO}}_{\text{2}}{}_{\left(\text{g}\right)}\text{at}\text{298K}$

Concept Introduction:

The equilibrium constant of a reaction can be calculated using the given expression,

  $\begin{array}{l}\text{lnK=}\frac{{\text{-ΔG}}_{\text{r}}{}^{\text{o}}}{\text{RT}}\\ \text{where,}\\ \text{R=gas constant (8}\text{.314}{\text{JK}}^{\text{-1}}{\text{mol}}^{\text{-1}}\text{)}\\ {\text{ΔG}}_{\text{r}}^{\text{°}}\text{=}\text{Standard}\text{Gibb's}\text{free}\text{energy}\\ \text{T}\text{=}\text{Temperature}\\ \text{K= equilibrium constant}\end{array}$